Algebra 1 Intermediate

Quadratic Equation Solver

Solve any quadratic equation using the quadratic formula, factoring, or completing the square — real and complex roots.

Live Calculator · Step-by-Step · Real & Complex Roots
Equation: ax² + bx + c = 0
x² − 5x + 6 = 0
x = (−b ± √(b²−4ac)) / (2a)
Examples
Divide by a → half (b/a) → add/subtract → square root
Examples
Find factors of a·c that sum to b. If not factorable, uses quadratic formula.
Examples
Solution
Enter a, b, c above and press Solve to see both roots, discriminant, vertex, and a parabola graph.
Δ = b²−4ac = —
Root x₁
Root x₂
Vertex (h, k)
Step-by-Step Solution
Parabola Graph
y = ax²+bx+c
Root(s)
Vertex
Axis of symmetry
Discriminant Key
Δ = b² − 4ac

Δ > 0 — Two distinct real roots. The parabola crosses the x-axis at two points.

Δ = 0 — One repeated real root (double root). The parabola is tangent to the x-axis at the vertex.

Δ < 0 — Two complex conjugate roots (a ± bi). The parabola does not cross the x-axis at all.

The discriminant also tells you the vertex y-value: k = −Δ/(4a). A negative k with a > 0 means two real roots.
Vieta's Formulas
x₁ + x₂ = −b/a    x₁ · x₂ = c/a

Vieta's formulas let you verify roots without substituting back. If x₁ and x₂ are your two roots:

Their sum must equal −b/a, and their product must equal c/a.

This is a fast mental check — especially handy when you factor by inspection.

  • Always check: does x₁ + x₂ = −b/a?
  • Always check: does x₁ · x₂ = c/a?
  • a ≠ 0 — if a = 0 the equation is linear, not quadratic.
  • Complex roots always come in conjugate pairs: a ± bi.

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