Algebra 1 Intermediate

Quadratic Formula

Solve ax² + bx + c = 0 using x = (−b ± √(b²−4ac)) / 2a. Enter a, b, and c to see the discriminant, exact roots, step-by-step work, and a parabola graph.

Discriminant analysis
Exact fraction roots
Parabola graph
Live
Equation: ax² + bx + c = 0
Enter values below to preview the equation
a (x² coefficient)
b (x coefficient)
c (constant)
Examples
Result
Enter values for a, b, and c above, then press Solve to see the roots and graph.
Discriminant   Δ = b² − 4ac
Step-by-Step Solution
Parabola Graph
The Quadratic Formula
x = (−b ± √(b² − 4ac)) / 2a

This formula solves any quadratic equation ax² + bx + c = 0 — even when factoring fails or the numbers are messy.

The expression under the radical, b² − 4ac, is called the discriminant (Δ). It tells you how many real solutions exist before you finish the calculation:

Δ > 0 — two distinct real roots  |  Δ = 0 — one repeated real root  |  Δ < 0 — no real roots (2 complex roots)

The ± sign gives two solutions: add √Δ for x₁ and subtract √Δ for x₂. Those are the x-intercepts of the parabola y = ax² + bx + c.

The vertex of the parabola is always at x = −b/(2a), exactly halfway between the two roots.
When to Use the Quadratic Formula

Three methods can solve a quadratic — choose wisely:

  • Factoring — fastest when the equation factors cleanly with integers. Try this first for small coefficients.
  • Completing the square — great for deriving the vertex form y = a(x−h)² + k and for proofs. More steps, but always works.
  • Quadratic formula — the all-purpose method. Use it when factoring fails, coefficients are large/ugly, or the discriminant is not a perfect square.
If the discriminant is a perfect square (1, 4, 9, 16, 25 …), the roots are rational — and the equation could have been factored.

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