SAT Math: Algebra, from the Diagnostic

A trial-session algebra deck: how the digital test is built and why module one accuracy matters most, a six-question timed diagnostic with one skill per question, then the named rules behind each miss — clearing fractions, distributing negatives, choosing between substitution, elimination and the graphing calculator, the 'for what value of k' systems question, flipping inequalities, and translating word problems — closing with an error log and a four-week plan.

Subject: SAT Prep · 61 slides · symbolic lesson

Open the interactive version of this deck · Homework for this lesson

What this lesson covers

The lesson, slide by slide

1. SAT Math: Algebra from the Diagnostic

Title

SAT Prep · trial session

Find where the points are leaking, then fix them one named rule at a time

2. What we are doing today

Objectives

You already know your own gaps, which puts you ahead of most people starting prep. Today is about turning 'algebra' into a short list of specific named rules, so that practice has a target.

Nothing today is a test of you. Every miss we find is a point we now know how to get back, which is the whole reason to look for them.

College Board — Digital SAT Suite Assessment Specifications: the Algebra domain is roughly 35 percent of the Math section — the Algebra domain is about 35 percent of the Math section

3. How the Test Is Built

Section

Section 1

4. Two sections, two modules each

Concept

Reading and Writing comes first, in two modules of twenty-seven questions with thirty-two minutes each. Math follows, in two modules of twenty-two questions with thirty-five minutes each. Each section is scored from two hundred to eight hundred.

The graphing calculator is built into every math question, and there is a reference sheet of formulas you never have to memorise.

College Board — Digital SAT Suite, including the official test description — the official test description

5. The shape of the test

Picture it

Four modules, and one feature that changes how you should think about the first one.

Figure (svg): Four rows showing the two Reading and Writing modules of twenty-seven questions in thirty-two minutes and the two Math modules of twenty-two questions in thirty-five minutes

Module two is chosen based on how module one went.

That last line matters more than anything else about the format: accuracy in module one is worth more than speed, because it decides which module two you are given.

6. Where should the care go?

Prediction

Given that module two adapts to module one.

Predict first

If you had to be more careful in one module, which?

  • Module 1
  • Module 2
  • Neither; they count equally
  • Whichever feels harder

Correct: Module 1.

Why: Module one decides which version of module two you receive, and the higher-scoring version is the one that makes the top of the range reachable. So the first module is worth a little extra care, and it is also the one where the questions are more evenly mixed in difficulty.

7. The sixty-second rule

Concept

This is the tool for the pressure you described. It is a habit rather than a tip, and it is the single change that moves scores fastest for students who know the content.

Before you start writing, decide how you are going to do the question: by hand, on the calculator, or not at all right now. Then, at about sixty seconds, ask whether you are on a path to an answer. If you are not, take your best guess, flag it, and move.

A student I worked with recently went from six hundred and ten to six hundred and seventy on math with this, and said it helped on Reading and Writing too.

College Board — Digital SAT Suite, including the official test description — the flag-and-review tool is built into the testing app

8. The rule, as four moves

Picture it

Pre-decide, clock, mark, return.

Figure (svg): A four step flow: decide the method before writing, check at sixty seconds whether you are on a path, guess and flag if not, and return with saved time

The point is that the time you spend at the end is time you saved, not time you borrowed.

The hardest part is the third box, because leaving a question feels like losing. It is the opposite: it is protecting three easy questions further on.

9. The Diagnostic

Section

Section 2

10. Six questions, timed, one skill each

Concept

Each question below targets exactly one thing, so that whatever happens the result points at a specific rule rather than at a vague area.

  1. A linear equation with fractions
  2. A system of two linear equations
  3. A linear function from two points, and what the slope means
  4. An inequality where the sign has to flip
  5. A word problem with a fixed cost and a rate
  6. One quadratic by factoring, to see how far past algebra you already are

Work them on paper, timed. We will sort the results together afterwards.

Khan Academy — Official Digital SAT Prep, Math — the same skill breakdown the official practice platform reports

11. Pattern: how to take a diagnostic

Pattern

Four rules, so that whatever happens the result is useful.

  1. Time it, honestly. An untimed result tells us about your knowledge and nothing about your test.
  2. Write the first line of working, even when you can see the answer. The first line is where we find the rule.
  3. Guess and move at sixty seconds. That is the habit we are here to build, and it starts now.
  4. Do not correct anything as you go. A clean record of what you did first is worth more than a tidy page.

Nothing here is graded, and there is no score at the end of it. We are looking for named rules, and a miss is how we find one.

12. Before the first question

Warm-up

One minute, no writing.

Discussion prompt

When you did your practice test, was there a question where you knew the method but still got it wrong? What happened on that one?

Hint: Think about the last few questions of a module rather than the hard ones.

Answer:

Almost always it is one of three things: a sign lost while distributing, the wrong quantity bubbled, or a rushed guess near the end of a module.

All three have specific fixes and none of them is 'be more careful'. That phrase is not actionable, which is why we are going to replace it today with named rules.

Khan Academy — Official Digital SAT Prep, Math — the official platform reports misses by skill for the same reason

13. Diagnostic 1: clear the fractions

Check

Two minutes. Show the first line of working.

Check your understanding

Solve for x: two-thirds of x, minus the quantity x minus 4 over 2, equals 3.

  • A. x = 6 (correct)
  • B. x = 2
  • C. x = 30
  • D. x = -6

Answer: A

Why: Multiply every term by 6: 4x minus 3 times the quantity x minus 4, equals 18. Distribute carefully to get 4x minus 3x plus 12 equals 18, so x equals 6. Check: two-thirds of 6 is 4, and 6 minus 4 over 2 is 1, and 4 minus 1 is 3.

Why B tempts people
This is what you get from distributing the negative wrongly, as minus 3x minus 12. That single sign is the most common error on this question type.
Why C tempts people
The 6 was multiplied through only on the left-hand side, so the right-hand side never became 18.
Why D tempts people
The subtraction was reversed at the end, giving the negative of the correct answer.

14. Diagnostic 2: a system

Check

Two minutes. Any method.

Check your understanding

If y equals 2x minus 1 and 3x plus y equals 14, what is the value of x?

  • A. 3 (correct)
  • B. 5
  • C. 2
  • D. 15

Answer: A

Why: One variable is already alone, so substitute: 3x plus 2x minus 1 equals 14, giving 5x equals 15 and x equals 3. Then y is 5.

Why B tempts people
That is y, not x. The question asked for x, and both values appear in the choices for exactly this reason.
Why C tempts people
This comes from dropping the minus one, so 5x equals 10.
Why D tempts people
This is 5x rather than x — one division short of the answer.

15. Diagnostic 3: the inequality

Check

One minute.

Check your understanding

Solve for x: negative 2x plus 5 is greater than 11.

  • A. x is less than -3 (correct)
  • B. x is greater than -3
  • C. x is less than 3
  • D. x is greater than 8

Answer: A

Why: Subtract 5 to get negative 2x greater than 6, then divide by negative 2 and reverse the sign, giving x less than negative 3. Check with x equal to negative 4: 8 plus 5 is 13, which is greater than 11.

Why B tempts people
The sign was not flipped when dividing by the negative. This is the single rule this question exists to test.
Why C tempts people
The negative was dropped from the 3 as well as the sign not being flipped.
Why D tempts people
The 5 was added rather than subtracted, and then the negative ignored.

16. Fixing the Rules

Section

Section 3

17. Sorting the results, out loud

Concept

Two columns, and the wording is deliberate. Anything correct goes under already solid. Anything missed goes under points we just found.

already solidpoints we just found
what you got right, at speedthe specific rule behind each miss
keep, do not re-drillthis is today's work

A found point is worth more than a solid one right now, because a found point is a score change and a solid one is not. That is not encouragement; it is arithmetic.

18. Worked example: clearing fractions without the sign error

Worked example

The first diagnostic question, done slowly.

Find the smallest number both denominators divide

Why: Three and two both divide six, so six is the multiplier.

Multiply every term, including the right-hand side

Why: Missing the right-hand side is the second most common error here, after the sign.

\[ 6 \cdot \frac{2x}{3} - 6 \cdot \frac{x-4}{2} = 6 \cdot 3 \]

\[ 4x - 3(x-4) = 18 \]

Distribute the negative into BOTH terms

Why: Minus three times x is minus three x, and minus three times minus four is plus twelve. The plus is the whole difficulty of this line.

\[ 4x - 3x + 12 = 18 \]

\[ x = 6 \]

Verify: by substituting back into the original

Why: Two-thirds of six is four, and six minus four over two is one. Four minus one is three, which matches. The check takes ten seconds and it catches the sign error every time it happens.

19. What clearing the denominators looks like

Picture it

One multiplication, applied to every term.

Figure (svg): A fractional equation being multiplied through by six to become an equation with no fractions

Do this before anything else; nothing else gets easier first.

20. Trap: distributing a negative into only the first term

Trap

The trap

The line everything depends on.

\[ -3(x - 4) = -3x - 12 \]

Multiply the negative three into x, then copy the rest

Why: The minus sign was applied once and then forgotten.

Get an answer of 2 instead of 6

Why: Both numbers are in the answer choices, so nothing about the result looks wrong.

The fix

Two multiplications, written out, every time.

\[ -3(x-4) = (-3)(x) + (-3)(-4) = -3x + 12 \]

Write the second product before simplifying

Why: Negative times negative is positive, and writing the intermediate line is what makes that visible.

Then substitute back

Why: The check is what makes this a rule you own rather than one you have been told.

21. Distribute it yourself

Fill the middle

The setup and the answer are given.

Fill in the blanks

4x - 3(x-4) = 18 \;\Rightarrow\; 4x - 3x + 12 = 18 \;\Rightarrow\; x = 6

Why: Both terms inside the bracket get multiplied by negative three, so the minus four becomes plus twelve. Collecting the x terms leaves x plus twelve, and subtracting twelve gives six.

22. Systems: three methods, one decision

Concept

Substitution when a variable is already alone. Elimination when the coefficients line up or cancel. The graphing calculator when the numbers are ugly or the clock is short.

All three give the same answer. Choosing quickly is what saves the time, not being good at any one of them.

OpenStax, Algebra and Trigonometry 2e Ch. 9

23. Choosing the method in five seconds

Picture it

Look at the equations before you touch them.

Figure (svg): A decision flow choosing substitution when a variable is isolated, elimination when coefficients cancel, and the graphing calculator when numbers are messy

The decision is made by looking, not by trying.

24. Worked example: elimination

Worked example

Two equations where the y terms cancel on sight.

\[ 2x + 3y = 12 \qquad \text{and} \qquad 4x - 3y = 6 \]

Notice the coefficients of y are opposites

Why: Plus three and minus three. Adding the equations removes y with no preparation at all.

\[ 6x = 18 \Rightarrow x = 3 \]

Substitute back into the simpler equation

Why: Six plus three y equals twelve, so three y is six and y is two.

\[ (3, 2) \]

Verify: in the equation you did not use

Why: Four times three minus three times two is twelve minus six, which is six. It checks, so both values are right rather than just consistent.

25. Reading the intersection off the screen

Picture it

The same system, done the other way.

Figure (svg): The Bluebook Desmos panel with two equations entered and their intersection at three comma five highlighted

Type both equations, click where they cross.

Worth it when the numbers are ugly. Not worth it here, where elimination took fifteen seconds and typing would take thirty.

26. The 'for what value of k' question

Concept

The test asks about systems with no solution or infinitely many solutions constantly, and always in the same disguise: a coefficient is replaced by a letter.

Two lines with the same slope never meet unless they are the same line. So compare the equations term by term and see whether one is a multiple of the other.

Khan Academy — Official Digital SAT Prep, Math — systems of linear equations

27. The two cases

Picture it

Same slope both times. The intercept decides everything.

Figure (svg): Two coordinate planes, the first with parallel lines that never meet and the second with two identical overlapping lines

Parallel means no solution; identical means infinitely many.

28. Worked example: find k for no solution

Worked example

For what value of k does the system have no solution?

\[ 3x + ky = 8 \qquad \text{and} \qquad 6x + 10y = 20 \]

Find the factor between the x coefficients

Why: Six is twice three, so if the lines are parallel the whole left side must scale by two.

Match the y coefficients under that factor

Why: Twice k must be ten, so k is five.

\[ 2k = 10 \Rightarrow k = 5 \]

Now check the constants, which is what decides which case it is

Why: Twice eight is sixteen, and the second equation says twenty. They disagree, so the lines are parallel rather than identical.

\[ k = 5 \Rightarrow \text{no solution} \]

Verify: by imagining the other outcome

Why: Had the second constant been sixteen instead of twenty, the same k would have given infinitely many solutions instead. The constant is the whole difference, and the test asks both versions.

29. Same k, two different answers

Picture it

The left column is this question; the right column is the version with a different constant.

Figure (svg): Two bars comparing a system whose constants disagree giving no solution against one whose constants agree giving infinitely many

Check the constant last, and it tells you which of the two answers to give.

30. Which is the right conclusion?

Elimination

A system where doubling the first equation matches the second on both variables but not on the constant.

Eliminate the wrong options

What can you say?

  • A. The lines are parallel, so there is no solution
  • B. The lines are the same, so there are infinitely many solutions
  • C. There is exactly one solution
  • D. There is not enough information

Survives elimination: A

Why: Two equations describe parallel lines exactly when the variable coefficients are proportional and the constants are not. That is the whole test, and it takes about ten seconds.

31. Functions, Inequalities and Words

Section

Section 4

32. Worked example: a linear function from two points

Worked example

A line passes through two, seven and five, sixteen. Find the equation, and say what the slope means.

Compute the slope as rise over run

Why: Sixteen minus seven is nine; five minus two is three.

\[ m = \frac{9}{3} = 3 \]

Find the starting value using either point

Why: Seven equals three times two plus b, so b is one.

\[ y = 3x + 1 \]

Say what the three means in context

Why: For each additional unit of x, y increases by three. That phrasing is the answer pattern the test wants.

Verify: with the second point

Why: Three times five plus one is sixteen, which matches. Always check with the point you did not use to find b.

33. Slope as a rate, intercept as a start

Picture it

The dashed steps show the rise and the run.

Figure (svg): A line through two comma seven and five comma sixteen with dashed run of three and rise of nine and the intercept at one marked

Slope three means three more y for every one more x.

When the test asks what a number represents in a context, this sentence pattern is the answer: for each additional unit of the input, the output changes by the slope.

34. Match the number to its meaning

Matching

A gym charges a thirty dollar signup fee plus fifteen dollars a month.

Match the pairs

  • l1. the 30
  • l2. the 15
  • l3. the value when m is zero
  • l4. the change when m increases by 1
  • r1. the starting cost, before any months
  • r2. the cost per month
  • r3. 30, the intercept
  • r4. 15, the slope

Why: Every linear word problem on this test has this shape: a fixed amount that does not depend on the variable, plus a rate that multiplies it. Naming which is which before writing the equation is the whole translation step.

35. Worked example: the word problem, translated line by line

Worked example

The gym charges thirty dollars to join and fifteen dollars a month. After how many whole months does the total exceed one hundred and eighty dollars?

Write the total as a fixed part plus a rate part

Why: Thirty does not depend on the number of months; fifteen multiplies it.

\[ C = 30 + 15m \]

Translate 'exceeds' into an inequality

Why: Exceeds means strictly greater than.

\[ 30 + 15m > 180 \]

Solve, then read the context

Why: Fifteen m is greater than one hundred and fifty, so m is greater than ten.

\[ m > 10 \Rightarrow m = 11 \]

Verify: both sides of the boundary

Why: At ten months the total is one hundred and eighty exactly, which does not exceed it. At eleven it is one hundred and ninety-five, which does. So eleven is right, and this is why 'exceeds' had to be a strict inequality.

36. Trap: forgetting to flip the inequality

Trap

The trap

Solving the third diagnostic question.

\[ -2x > 6 \;\Rightarrow\; x > -3 \]

Divide both sides by negative two and keep the direction

Why: Every other operation preserves the direction, so this one is easy to do on autopilot.

Get exactly the wrong half of the number line

Why: And the wrong half is always one of the answer choices.

The fix

Flip when you multiply or divide by a negative, and only then.

\[ -2x > 6 \;\Rightarrow\; x < -3 \]

Test one number from your answer

Why: Try negative four: two times four is eight, plus five is thirteen, which is greater than eleven. It works, so the direction is right.

Use the test point on graphing questions too

Why: For a shaded-region question, try the origin. If it satisfies the inequality, the origin is in the shaded region.

37. Which half of the line

Picture it

The solution is everything to the left of negative three.

Figure (svg): A number line shaded to the left of negative three with a hollow circle at negative three

Hollow circle because negative three itself does not satisfy a strict inequality.

38. Translate each phrase

Translation

Word problems are a translation exercise, and the dictionary is short.

Match the pairs

  • l1. per, each
  • l2. total, combined
  • l3. 5 less than x
  • l4. is, was, will be
  • l5. of
  • r1. multiply by the count
  • r2. add
  • r3. x minus 5, in that order
  • r4. equals
  • r5. multiply

Why: The third one is the trap: 'five less than x' reverses the order of what you read, giving x minus five rather than five minus x. Translate line by line rather than reading the whole problem and then writing an equation from memory.

39. Pattern: the algebra checklist

Pattern

Six rules. Between them they cover most of what the Algebra domain asks.

  1. Fractions: multiply every term by the common denominator, including the right-hand side.
  2. Negatives: distribute into every term inside the bracket, and write the intermediate line.
  3. Systems: substitute if a variable is alone, eliminate if coefficients cancel, graph if it is ugly.
  4. No solution or infinitely many: scale term by term, and let the constant decide which.
  5. Inequalities: flip only for a negative multiply or divide, then test one number.
  6. Word problems: fixed part plus rate part, translated line by line.
before you bubblewhy
reread the last line of the questionx, 2x and x plus 3 are all in the choices
check units and whole numberseleven months, not ten point something
substitute your answer backcatches every sign error

College Board — Digital SAT Suite Assessment Specifications: the Algebra domain is roughly 35 percent of the Math section — the Algebra domain

40. Check: the careless-error trap

Check

Solve it on paper before you click.

Check your understanding

If 5x minus 3 equals 12, what is the value of 10x minus 6?

  • A. 24 (correct)
  • B. 3
  • C. 12
  • D. 30

Answer: A

Why: The target is exactly double the given expression, so double both sides: 10x minus 6 is twice 12, which is 24. Solving for x also works and gives x equal to 3, then 30 minus 6 equals 24.

Why B tempts people
That is x, which the question did not ask for. This is the single most common way to lose a question you solved correctly.
Why C tempts people
That is the value of the original expression, copied across without doubling.
Why D tempts people
That is 10x, one subtraction short of the answer.

41. Check: interpret the slope

Check

Solve it on paper before you click.

Check your understanding

A plan costs C equals 45 plus 12h, where h is hours of service. What does the 12 represent?

  • A. For each additional hour, the cost increases by 12 dollars (correct)
  • B. The total cost is 12 dollars
  • C. The service takes 12 hours
  • D. The starting cost before any hours

Answer: A

Why: The number multiplying the variable is a rate: cost per hour. The answer pattern the test rewards is 'for each additional unit of the input, the output changes by this much'.

Why B tempts people
The total is the whole expression, and it depends on how many hours are used.
Why C tempts people
Twelve is a rate in dollars per hour, not a number of hours. Reading units prevents this.
Why D tempts people
That is the 45, which is the part that does not depend on h.

42. Which method for each system?

Sorting

Look at the equations only. Do not solve any of them.

Sort into buckets

Substitute, eliminate, or graph?

substitute
y = 4x + 2, and 3x + y = 16; x = 7 - 2y, and 4x + 3y = 13
eliminate
5x + 2y = 11, and 5x - 2y = 9
graph it
0.35x + 1.2y = 8.4, and 2.7x - 0.9y = 3.15
sub
A variable is already alone on one side, so substituting costs one line and no rearranging.
elim
The coefficients of one variable are equal or opposite, so adding or subtracting the equations removes it immediately.
graph
The numbers are decimals that would make hand arithmetic slow and error-prone, which is exactly what the built-in calculator is for.

Making this decision in five seconds, before touching anything, is worth more than being fast at any one method.

43. Find the slip

Error analysis

A first attempt at clearing the denominators.

Annotate

On: \( \frac{x}{4} + \frac{x-1}{3} = 2 \;\Rightarrow\; 3x + 4(x-1) = 2 \)

  • The left-hand side is correct: twelve times each fraction gives 3x and 4 times the quantity x minus 1.
  • The right-hand side was not multiplied. It should be 24, not 2.
  • Correct: 3x plus 4x minus 4 equals 24, so 7x equals 28 and x equals 4.

Multiplying every term means every term, including the one with no fraction in it. Checking by substituting back catches this instantly.

44. Estimate before solving

Estimation

A gym charges thirty dollars to join plus fifteen a month.

Predict first

Roughly how many months until the total passes two hundred dollars?

  • About 6
  • About 11
  • About 13
  • About 20

Correct: About 11.

Why: Ignore the joining fee for a second: two hundred divided by fifteen is a bit over thirteen. The thirty dollar fee covers about two months of that, so the answer is around eleven. Estimating first means an answer of six or twenty gets rejected before you check anything.

45. Quadratics, If You Are Ready

Section

Section 5

46. Three forms, three facts

Concept

Beyond linear algebra the test moves to quadratics, and the same expression gets written three ways depending on what the question is hiding.

\[ y = x^2 - 5x + 6 = (x-2)(x-3) = (x - 2.5)^2 - 0.25 \]

Standard form gives the y-intercept, factored form gives the roots, and vertex form gives the minimum. Recognising which form you have been handed is most of the question.

OpenStax, Algebra and Trigonometry 2e Ch. 5

47. Which form answers which question

Picture it

The same parabola, three times.

Figure (svg): Three rows pairing standard, factored and vertex form with the fact each one reveals

The test chooses the form that hides what it asks for.

48. Worked example: solve by factoring

Worked example

Solve the equation whose standard form has a leading coefficient of one, a linear coefficient of negative five and a constant of six.

Find two numbers multiplying to the constant and adding to the linear coefficient

Why: Negative two and negative three multiply to six and add to negative five.

\[ (x-2)(x-3) = 0 \]

Set each factor to zero

Why: A product is zero exactly when one of its factors is.

\[ x = 2 \quad \text{or} \quad x = 3 \]

Verify: by substituting the smaller root

Why: Four minus ten plus six is zero. And the two roots average to two point five, which is the vertex input from the vertex form, so all three forms agree.

49. All three facts on one curve

Picture it

Roots, vertex and intercept, marked.

Figure (svg): A parabola crossing at two and three with the vertex at two point five and the y-intercept at six marked

The axis of symmetry sits exactly halfway between the roots.

That halfway shortcut is worth knowing: if a question gives you the roots and asks for the vertex, you can average them and skip the algebra.

50. Linear or quadratic?

Discrimination

The shape of the equation tells you which toolkit to open.

Sort into buckets

Which kind of equation is each?

linear
3x + 7 = 22; 2(x - 5) = x + 1
quadratic
x squared minus 4 = 0; x times the quantity x plus 3, equals 10
lin
The variable appears only to the first power once everything is expanded, so isolating it works.
quad
There is a squared term, or one appears after expanding a product of two brackets. Move everything to one side and factor.

51. Explain the sixty-second rule to a friend

Explain it

Two sentences, out loud.

Discussion prompt

Why is guessing and moving on at sixty seconds better than pushing through a hard question?

Hint: Compare the value of the hard question against the value of the two questions at the end you never reached.

Answer:

Because every question is worth the same, and a minute spent on a hard one is a minute taken from two easier ones later in the module.

And you can come back. Flagging costs nothing, and returning with a fresh look often solves in twenty seconds what was stuck for two minutes.

College Board — Digital SAT Suite, including the official test description — the flag and review tool

52. How sure are you?

Commit first

Answer, then rate your confidence honestly. Confident and wrong is the useful combination to find.

Predict first

If 4x + 8 = 20, what is the value of x + 2?

  • 5
  • 3
  • 12
  • 2

Correct: 5.

Why: Divide the whole equation by 4: x plus 2 equals 5. No solving for x is needed at all. Solving anyway gives x equal to 3, which is the distractor sitting in the choices for exactly that reason.

53. Which pacing claim holds?

Two truths and a lie

Three statements about the digital test.

Eliminate the wrong options

Which is true?

  • A. Accuracy in module one matters more than finishing it quickly, because it decides which module two you get.
  • B. You should always finish every question in order.
  • C. There is a penalty for a wrong answer, so leaving it blank is safer.
  • D. The calculator is only available on some math questions.

Survives elimination: A

Why: The adaptive structure is the one genuinely new thing about the digital format, and it changes the priority: get module one right rather than fast, and never leave a blank anywhere.

54. Where this shows up outside the test

Real world

A phone plan costs twenty-five dollars a month plus eight cents a minute.

Discussion prompt

Write the cost as an equation, and say what each number means.

Hint: Which number does not depend on how much you use it?

Answer:

Cost equals twenty-five plus zero point zero eight times the number of minutes.

Twenty-five is the fixed part, paid whether or not you make a call. Eight cents is the rate, the amount the total changes for each extra minute.

It is the same structure as the gym problem, and as almost every linear word problem on the test: a fixed part plus a rate part.

55. Making Progress Visible

Section

Section 6

56. The error log

Concept

Every missed question gets one row, written the same day, with four columns: the question, what you did, the rule, and whether you would get it now.

The third column is the important one. A miss recorded as a rule is a thing you can fix. A miss recorded as 'careless' is not.

Khan Academy — Official Digital SAT Prep, Math — reviewing misses by skill is what the official platform reports too

57. What a row looks like

Picture it

Three real rows from a first week.

Figure (svg): An error log table with columns for the question, what the student did, the rule, and whether they would get it now

Every row names a rule, and no row names the student.

After two weeks the third column starts repeating, and the repeats are the study plan. It writes itself.

58. Four weeks, and what to expect from them

Concept

A mid-September test gives roughly four weeks. Two sessions a week plus about twenty minutes a day of practice is enough time if it is aimed.

weekmathreading and writing
1linear equations, systems, functionspunctuation between clauses
2quadratics and exponents, first timed modulesubject-verb agreement, pronouns
3problem solving and data, geometry basicstransitions and vocabulary in context
4two full timed tests, pacing drills, tapererror-log review across all four weeks

Scores move in steps, not in a line. A flat week is normal and expected, which is why we track module accuracy and the error log rather than only the headline number.

College Board — Digital SAT Suite, including the official test description — official full-length practice tests for weeks three and four

59. Exit ticket

Exit ticket

One honest answer. There is no wrong one, and it decides what we open with next time.

Predict first

Of everything today, which felt least automatic?

  • Clearing fractions and distributing negatives
  • Choosing a method for a system
  • The 'for what value of k' question
  • Flipping the inequality sign
  • Translating a word problem
  • Pacing, and leaving a question alone

Correct: Whichever you picked is where we start next session.

Why: Every item on that list is a named rule with a fifteen-minute fix, which is exactly why we spent today turning 'algebra' into this list. Naming the weak one is worth more than another pass over the strong ones.

60. Start the log tonight

Connect it up

Ten minutes, and then stop.

Draw it

Take the practice test you already did. Pick the five math questions you missed and write one error-log row for each: what you did, the rule, and whether you would get it now.

Bring the five rows next session. They are a better plan than anything either of us could invent in advance.

61. What we found today

Recap

The point of the diagnostic was not the score. It was turning one word, algebra, into a short list of named rules.

questionanswerthe rule it tested
fractions equationx = 6multiply every term, distribute the negative
substitution systemx = 3, y = 5substitute when a variable is alone
elimination system(3, 2)add when coefficients are opposites
no solutionk = 5constants decide the case
inequalityx less than -3flip for a negative divide
gym word problem11 monthsfixed part plus rate part

College Board — Digital SAT Suite, including the official test description — official practice, and the site's own SAT page for daily drilling

Sources

  1. College Board — Digital SAT Suite, including the official test description
  2. College Board — Digital SAT Suite Assessment Specifications: the Algebra domain is roughly 35 percent of the Math section — College Board, 2023
  3. Khan Academy — Official Digital SAT Prep, Math
  4. Desmos graphing calculator, the version built into Bluebook
  5. OpenStax, Algebra and Trigonometry 2e

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