An hour-length bridge deck of 40 slides that fills a full tutoring hour. It covers solving inequalities, graphing them on a number line, reasoning about when the sign flips, compound inequalities, function notation, and domain and range, then moves through guided practice and independent practice, with traps and checks along the way.
Subject: Algebra 2 Readiness · 94 slides · symbolic lesson
Open the interactive version of this deck · Homework for this lesson
Objectives
By the end of this hour you can:
1. Solve inequalities and know when the direction reverses.
2. Graph solution sets with correct endpoints and shading.
3. Translate compound inequalities as overlap or union.
4. Evaluate function notation as input-output language.
5. Find domain and range from tables, graphs, and simple formulas.
Warm-up
Discussion prompt
Before we open Week 2: Inequalities, Graphing, and Functions: without looking back, what was the main idea of Week 1: Expressions, Equations, and Literal Equations, and what could you do by the end of it that you could not do before?
Hint: One sentence for the idea, one for the skill. If the second one is blank, that is the part to revisit.
Answer:
An hour-length bridge deck of 40 slides that fills a full tutoring hour. It covers terms and like terms, distribution, working with negative signs, multi-step equations, and literal equations, then moves through guided practice and independent practice, with traps and checks along the way.
Concept
This hour alternates between solving, graphing, and explaining the meaning of the answer.
| Part | Minutes | Job |
|---|---|---|
| warm-up | 0-8 | compare equations and inequalities |
| inequalities | 8-25 | solve and graph one-step and two-step inequalities |
| compound statements | 25-35 | and versus or |
| functions | 35-50 | evaluate and track input-output pairs |
| domain/range | 50-60 | read allowed inputs and outputs |
Comparison
Comparison matrix
From How this hour will run: refill the Minutes column from what you know. The rest of the table is as it appeared.
| Part | Minutes | Job |
|---|---|---|
| warm-up | 0-8 | compare equations and inequalities |
| inequalities | 8-25 | solve and graph one-step and two-step inequalities |
| compound statements | 25-35 | and versus or |
| functions | 35-50 | evaluate and track input-output pairs |
| domain/range | 50-60 | read allowed inputs and outputs |
Concept
An equation often has one exact answer. An inequality usually has a whole set of answers.
| Statement | Answer type |
|---|---|
| x + 3 = 7 | one value |
| x + 3 < 7 | all values below a boundary |
| x >= -3 and x < 4 | an interval of values |
Trade off
Comparison matrix
From Equation answers versus inequality answers: every row here is a choice with a cost. Fill the Answer type column, then say which row you would actually pick and what you give up for it.
| Statement | Answer type |
|---|---|
| x + 3 = 7 | one value |
| x + 3 < 7 | all values below a boundary |
| x >= -3 and x < 4 | an interval of values |
Ranking
Put in order
Put the moves of Model: one-step inequality into the order they have to happen.
Why: These are the moves of the worked example in the order it makes them, and each one is set up by the one before it. Undo the added constant while keeping the inequality equivalent.
Worked example
Solve and describe the solution:
\[ x+3\le 7 \]
Subtract three from both sides
Why: Undo the added constant while keeping the inequality equivalent.
\[ x\le4 \]
Decide endpoint type
Why: The solution includes four because the symbol allows equality.
| endpoint | circle |
|---|---|
| 4 | closed |
Shade the correct side
Why: Values less than or equal to four are to the left.
\[ \longleftarrow\!\!\!\bullet\quad\text{at }4 \]
Check with one inside and one outside value
Why: Four works, zero works, and five does not.
\[ 4+3=7\checkmark\quad\text{but}\quad5+3=8\not\le7 \]
Picture it
Animation
Shows: Each line of the worked example "Model: one-step inequality", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Four works, zero works, and five does not.
Step zero
Discussion prompt
Guided try: one-step inequality — before any calculation: what is the plan? Name the moves in order, in plain English, without doing the arithmetic.
Hint: It starts with: Hint: undo subtraction
Answer:
Worked example
Your turn: work this on paper before you reveal the hint.
\[ x - 5 > -2 \]
Hint: undo subtraction
Why: Use the inverse operation on both sides.
Add five to both sides
Why: This leaves the variable alone.
\[ x>3 \]
Choose the graph endpoint
Why: The endpoint is open because three is not included.
\[ \circ\!\!\!\longrightarrow\quad\text{at }3 \]
Check with one inside and one outside value
Why: Four works, but three does not.
\[ 4-5=-1>-2\checkmark\quad\text{but}\quad3-5=-2\not>-2 \]
Picture it
Animation
Shows: Each line of the worked example "Guided try: one-step inequality", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: The endpoint is open because three is not included.
Concept
The symbol decides whether the boundary point is included. The direction decides which side gets shaded.
| Symbol | Circle | Shade |
|---|---|---|
| less than | open | left |
| less than or equal | closed | left |
| greater than | open | right |
| greater than or equal | closed | right |
Discrimination
Sort into buckets
Sort these by Circle, from memory, without looking back at Graphing inequality endpoints. Telling them apart on the spot is the skill; the table is only where the answer happens to be written down.
Worked example
Graph the solution:
\[ x\ge -3 \]
Place the boundary at negative three
Why: The boundary is the number next to the variable.
\[ -3 \]
Use a closed circle
Why: The equality part means the endpoint is included.
\[ \bullet\quad\text{at }-3 \]
Shade right
Why: Greater values live to the right on the number line.
\[ \bullet\!\!\!\longrightarrow\quad\text{from }-3 \]
Check the graph with sample values
Why: Negative three and zero work; negative four does not.
\[ -3\text{ works},\quad0\text{ works},\quad-4\text{ fails}\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Model: read a graph from notation", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Negative three and zero work; negative four does not.
Estimation
Predict first
Your turn: work this on paper before you reveal the hint.
Commit before you compute: what does Independent try: graph from notation come out to? A rough magnitude and the right form is enough — the point is to have something concrete to be wrong about.
Correct: Check with sample values
Why: A prediction you can defend turns the computation into a check rather than a leap of faith — and an answer that contradicts it is caught on the spot. One works, two does not, and three does not.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ x < 2 \]
Hint: strict symbol means open endpoint
Why: Decide the circle first, then the shading direction.
Use an open circle at two
Why: The endpoint is not included.
\[ \circ\quad\text{at }2 \]
Shade left
Why: Values less than two live to the left.
\[ \longleftarrow\!\!\!\circ\quad\text{at }2 \]
Check with sample values
Why: One works, two does not, and three does not.
\[ 1<2\checkmark\quad2\not<2\quad3\not<2 \]
Picture it
Animation
Shows: Each line of the worked example "Independent try: graph from notation", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: One works, two does not, and three does not.
Concept
Most inequality moves are equation moves. The exception happens when multiplying or dividing by a negative number.
\[ -2x+5<13 \]
Negative scaling reverses order, so the inequality direction reverses too.
Counterexample
Discussion prompt
Most inequality moves are equation moves. The exception happens when multiplying or dividing by a negative number.
That is stated as though it always holds. Do one of two things: produce a case where it fails, or say precisely what rules such a case out. "It just does" is not on the menu.
Hint: Hunt at the extremes first — zero, one, negative, empty, equal. If every extreme survives, the reason they survive is the proof.
Answer:
Negative scaling reverses order, so the inequality direction reverses too.
Intuition
Multiplying by a negative reflects the number line across zero. Left and right switch places.
| Before multiplying by negative one | After multiplying by negative one |
|---|---|
| 3 is greater than 1 | -3 is less than -1 |
| -5 is less than 2 | 5 is greater than -2 |
That reflection is why the sign flips when you divide by a negative.
Analogy
Discussion prompt
Explain Why the symbol reverses by analogy to something with no Algebra 2 Readiness in it at all — a queue, a recipe, a map, a bank balance, whatever fits. Then say where your analogy breaks.
Hint: An analogy that never breaks is not an analogy, it is the same idea wearing a hat. Find the seam — that is the part that is actually new.
Answer:
Multiplying by a negative reflects the number line across zero. Left and right switch places.
Worked example
Solve and graph:
\[ -2x+5<13 \]
Subtract five from both sides
Why: Clear the constant first.
\[ -2x<8 \]
Divide by negative two
Why: This is the special move that reverses the inequality.
\[ x>-4 \]
Graph with open endpoint and shade right
Why: The endpoint is not included, and greater values are to the right.
\[ \circ\!\!\!\longrightarrow\quad\text{at }-4 \]
Verify with inside and outside values
Why: Negative three works; negative five fails.
\[ -2(-3)+5=11<13\checkmark\quad\text{but}\quad-2(-5)+5=15\not<13 \]
Picture it
Animation
Shows: Each line of the worked example "Model: solve and graph with a flip", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Negative three works; negative five fails.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ -3x - 4 \le 8 \]
Hint: isolate the variable term first
Why: After you divide by negative three, reverse the inequality.
Add four to both sides
Why: This leaves the variable term alone.
\[ -3x\le12 \]
Divide by negative three and reverse
Why: Negative division flips the direction.
\[ x\ge-4 \]
Graph with a closed endpoint and shade right
Why: The equality part includes the boundary.
\[ \bullet\!\!\!\longrightarrow\quad\text{at }-4 \]
Check with sample values
Why: Negative four works, zero works, and negative five fails.
\[ -3(-4)-4=8\checkmark\quad\text{but}\quad-3(-5)-4=11\not\le8 \]
Picture it
Animation
Shows: Each line of the worked example "Guided try: negative division", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Negative four works, zero works, and negative five fails.
Anomaly
Predict first
A student writes this, and it looks reasonable:
Subtract five from both sides
It is wrong. Say what breaks — and say it before you turn the page.
Correct: The division happened, but the order reversal was missed.
The division happened, but the order reversal was missed.
Why: The division happened, but the order reversal was missed.
Trap
\[ -2x+5<13 \]
Subtract five from both sides
Why: This first move is legal.
\[ -2x<8 \]
Divide by negative two but keep the direction
Why: The division happened, but the order reversal was missed.
\[ x<-4 \]
Check a claimed solution
Why: Negative five is on the claimed side, but it fails the original inequality.
\[ -2(-5)+5=15\not<13 \]
\[ -2x+5<13 \]
Subtract five from both sides
Why: Same legal first move.
\[ -2x<8 \]
Divide by negative two and reverse the direction
Why: Negative division reflects the number line.
\[ x>-4 \]
Check a correct-side value
Why: Negative three satisfies the original inequality.
\[ -2(-3)+5=11<13\checkmark \]
Notation
Annotate
From Trap: forgetting the flip — read this one piece at a time. What is each part doing?
On: \( -2(-5)+5=15\not<13 \)
Concept
Compound statements describe how solution regions combine.
| Word | Meaning | Graph behavior |
|---|---|---|
| and | both conditions must be true | overlap only |
| or | at least one condition may be true | union of regions |
\[ x\ge -3\quad\text{and}\quad x<4 \]
Comparison
Comparison matrix
From Compound inequalities: and versus or: refill the Graph behavior column from what you know. The rest of the table is as it appeared.
| Word | Meaning | Graph behavior |
|---|---|---|
| and | both conditions must be true | overlap only |
| or | at least one condition may be true | union of regions |
Step zero
Discussion prompt
Model: graph an and statement — before any calculation: what is the plan? Name the moves in order, in plain English, without doing the arithmetic.
Hint: It starts with: Handle the left boundary
Answer:
Worked example
Describe and graph:
\[ x\ge -3\quad\text{and}\quad x<4 \]
Handle the left boundary
Why: Negative three is included.
\[ x\ge-3 \]
Handle the right boundary
Why: Four is not included.
\[ x<4 \]
Shade only the overlap
Why: An and statement needs both conditions at once.
\[ -3\le x<4 \]
Check endpoints and an inside value
Why: Negative three works, four does not, and zero works.
\[ -3\text{ works},\quad4\text{ fails},\quad0\text{ works}\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Model: graph an and statement", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Negative three works, four does not, and zero works.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ -1<x\le5 \]
Hint: read the two boundaries separately
Why: The left endpoint is strict and the right endpoint includes equality.
Use an open endpoint at negative one
Why: The value negative one is not included.
\[ -1<x \]
Use a closed endpoint at five
Why: The value five is included.
\[ x\le5 \]
Shade the overlap between the endpoints
Why: The solution is the interval between them.
\[ -1<x\le5 \]
Check endpoints and an inside value
Why: Zero and five work; negative one does not.
\[ 0\text{ works},\quad5\text{ works},\quad-1\text{ fails}\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Guided try: graph another and statement", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Zero and five work; negative one does not.
Worked example
Describe and graph:
\[ x<-2\quad\text{or}\quad x\ge3 \]
Graph the first region
Why: Values less than negative two go left from an open endpoint.
\[ \longleftarrow\!\!\!\circ\quad\text{at }-2 \]
Graph the second region
Why: Values greater than or equal to three go right from a closed endpoint.
\[ \bullet\!\!\!\longrightarrow\quad\text{at }3 \]
Keep both regions
Why: An or statement uses the union, not the overlap.
\[ x<-2\quad\text{or}\quad x\ge3 \]
Check one value from each region and one gap value
Why: Negative three works, three works, and zero fails.
\[ -3\text{ works},\quad3\text{ works},\quad0\text{ fails}\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Model: graph an or statement", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Negative three works, three works, and zero fails.
Ranking
Put in order
Put the moves of Independent try: translate words to compound inequality into the order they have to happen.
Why: These are the moves of the worked example in the order it makes them, and each one is set up by the one before it. Write the lower boundary first, then the upper boundary.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ t\text{ is at least }10\text{ and less than }18 \]
Hint: at least means included
Why: Write the lower boundary first, then the upper boundary.
Translate the lower boundary
Why: At least ten means ten is included.
\[ t\ge10 \]
Translate the upper boundary
Why: Less than eighteen means eighteen is not included.
\[ t<18 \]
Combine with and
Why: The value must satisfy both boundaries.
\[ 10\le t<18 \]
Check with examples
Why: Ten and seventeen work; eighteen does not.
\[ 10\text{ works},\quad17\text{ works},\quad18\text{ fails}\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Independent try: translate words to compound inequality", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Ten and seventeen work; eighteen does not.
Concept
Function notation names a rule and an input. It asks for the output produced by that input.
\[ f(x)=2x^2-3 \]
input — The value substituted into the rule.
output — The value produced after following the rule.
Analogy
Discussion prompt
Explain Function notation is not multiplication by analogy to something with no Algebra 2 Readiness in it at all — a queue, a recipe, a map, a bank balance, whatever fits. Then say where your analogy breaks.
Hint: An analogy that never breaks is not an analogy, it is the same idea wearing a hat. Find the seam — that is the part that is actually new.
Answer:
Function notation names a rule and an input. It asks for the output produced by that input.
Fill the middle
Fill in the blanks
From Model: evaluate a function — finish the line. Write what belongs on the right of the equals sign before you look.
f(x) = 2x^2-3\qquad f(-2)
Why: Producing the right-hand side unprompted is the difference between recognising this line and being able to use it. Order of operations puts the exponent before the coefficient multiplication.
Worked example
Evaluate:
\[ f(x)=2x^2-3\qquad f(-2) \]
Substitute the input everywhere the variable appears
Why: Parentheses protect the negative input.
\[ f(-2)=2(-2)^2-3 \]
Square before multiplying
Why: Order of operations puts the exponent before the coefficient multiplication.
\[ f(-2)=2(4)-3 \]
Finish the arithmetic
Why: The output is the final value.
\[ f(-2)=5 \]
Verify by tracking the input-output pair
Why: Input negative two produces output five.
| input | rule work | output |
|---|---|---|
| -2 | 2(4)-3 | 5 |
Picture it
Animation
Shows: Each line of the worked example "Model: evaluate a function", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Input negative two produces output five.
Hypothesis
Predict first
Guided try: evaluate with a positive input is about to be worked. State your hypothesis first: which rule or definition decides this one, and what is the first move it forces? Then watch whether the example agrees with you.
Correct: Hint: substitute the input twice
Why: The same input goes into every copy of the variable.
A hypothesis you wrote down is falsifiable; a vague sense of how it will go is not. If the example opens somewhere else, that gap is the thing worth chasing.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ g(x)=x^2-4x\qquad g(3) \]
Hint: substitute the input twice
Why: The same input goes into every copy of the variable.
Substitute three into both variable positions
Why: Use parentheses around the input.
\[ g(3)=(3)^2-4(3) \]
Square first, then multiply
Why: Follow order of operations.
\[ g(3)=9-12 \]
Finish the arithmetic
Why: The output is negative three.
\[ g(3)=-3 \]
Check by recording the ordered pair
Why: The input-output pair is three, negative three.
| input | output |
|---|---|
| 3 | -3 |
Picture it
Animation
Shows: Each line of the worked example "Guided try: evaluate with a positive input", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: The input-output pair is three, negative three.
Anomaly
Predict first
A student writes this, and it looks reasonable:
Read the notation as a product
It is wrong. Say what breaks — and say it before you turn the page.
Correct: This ignores the rule that defines the function.
This ignores the rule that defines the function.
Why: This ignores the rule that defines the function.
Trap
\[ f(x)=2x^2-3\qquad f(-2) \]
Read the notation as a product
Why: This ignores the rule that defines the function.
\[ f(-2)=-2f \]
Notice the problem
Why: The answer still has the function name in it, so no numerical output was found.
\[ -2f\quad\text{is not an output} \]
\[ f(x)=2x^2-3\qquad f(-2) \]
Use the rule and substitute the input
Why: The notation asks for the output when the input is negative two.
\[ f(-2)=2(-2)^2-3 \]
Finish the rule
Why: The input produces a number.
\[ f(-2)=5\checkmark \]
Notation
Annotate
From Trap: treating function notation like multiplication — read this one piece at a time. What is each part doing?
On: \( f(x)=2x^2-3\qquad f(-2) \)
Concept
Domain is the set of allowed inputs. Range is the set of outputs that actually appear.
| input | output |
|---|---|
| -2 | 5 |
| 0 | -3 |
| 3 | 15 |
Pattern
Step through it
Step through Domain and range from a table one row at a time. What is driving the change, and what would the row after the last one be?
Step zero
Discussion prompt
Model: find domain and range from a table — before any calculation: what is the plan? Name the moves in order, in plain English, without doing the arithmetic.
Hint: It starts with: List the input values
Answer:
Worked example
Use the table to name the domain and range.
| input | output |
|---|---|
| -2 | 5 |
| 0 | -3 |
| 3 | 15 |
List the input values
Why: Domain comes from the input column.
\[ \{-2,0,3\} \]
List the output values
Why: Range comes from the output column.
\[ \{-3,5,15\} \]
Put values in a clean order
Why: Ordering helps the student see duplicates and missing values.
| domain | range |
|---|---|
| {-2, 0, 3} | {-3, 5, 15} |
Check by pointing back to the table
Why: Every listed value appears in its correct column.
| set | source column |
|---|---|
| domain | input |
| range | output |
Picture it
Animation
Shows: Each line of the worked example "Model: find domain and range from a table", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Every listed value appears in its correct column.
Estimation
Predict first
Your turn: work this on paper before you reveal the hint.
Commit before you compute: what does Independent try: domain and range from a table come out to? A rough magnitude and the right form is enough — the point is to have something concrete to be wrong about.
Correct: Check by matching each table row
Why: A prediction you can defend turns the computation into a check rather than a leap of faith — and an answer that contradicts it is caught on the spot. Every table row uses an input from the domain and output from the range.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ \begin{array}{c|c}x&h(x)\\-1&4\\2&4\\5&9\end{array} \]
Hint: duplicates are listed once
Why: Domain comes from inputs; range comes from outputs.
List the inputs
Why: Use the left column.
\[ \{-1,2,5\} \]
List the outputs once each
Why: The output four appears twice but belongs in the range once.
\[ \{4,9\} \]
Check by matching each table row
Why: Every table row uses an input from the domain and output from the range.
| domain | range |
|---|---|
| {-1, 2, 5} | {4, 9} |
Picture it
Animation
Shows: Each line of the worked example "Independent try: domain and range from a table", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Every table row uses an input from the domain and output from the range.
Concept
Some formulas forbid inputs that make a denominator zero.
\[ r(x)=\frac{1}{x-4} \]
Ask which input would break the rule, then exclude it.
Counterexample
Discussion prompt
Some formulas forbid inputs that make a denominator zero.
That is stated as though it always holds. Do one of two things: produce a case where it fails, or say precisely what rules such a case out. "It just does" is not on the menu.
Hint: Hunt at the extremes first — zero, one, negative, empty, equal. If every extreme survives, the reason they survive is the proof.
Answer:
Ask which input would break the rule, then exclude it.
Fill the middle
Fill in the blanks
From Model: find a formula domain — finish the line. Write what belongs on the right of the equals sign before you look.
r(x) = \frac{1}{x-4}
Why: Producing the right-hand side unprompted is the difference between recognising this line and being able to use it. This identifies the input that would break the formula.
Worked example
Find the domain:
\[ r(x)=\frac{1}{x-4} \]
Find the denominator
Why: Division by zero is not allowed.
\[ x-4 \]
Set the denominator equal to zero
Why: This identifies the input that would break the formula.
\[ x-4=0 \]
Solve for the excluded input
Why: Four makes the denominator zero.
\[ x=4 \]
Check by testing the excluded input
Why: At four, the denominator is zero, so four is not allowed.
\[ r(4)=\frac{1}{0}\quad\text{not allowed} \]
Picture it
Animation
Shows: Each line of the worked example "Model: find a formula domain", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: At four, the denominator is zero, so four is not allowed.
Fill the middle
Fill in the blanks
From Guided try: another formula domain — finish the line. Write what belongs on the right of the equals sign before you look.
p(-2) = \frac{5}{0}\quad\text{not allowed}
Why: Producing the right-hand side unprompted is the difference between recognising this line and being able to use it. Solve the small equation that makes the denominator zero.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ p(x)=\frac{5}{x+2} \]
Hint: the denominator cannot equal zero
Why: Solve the small equation that makes the denominator zero.
Set the denominator equal to zero
Why: This finds the input that must be excluded.
\[ x+2=0 \]
Solve the small equation
Why: Subtract two from both sides.
\[ x=-2 \]
State the domain
Why: All real inputs are allowed except negative two.
\[ x\ne-2 \]
Check by testing the excluded input
Why: Negative two creates division by zero.
\[ p(-2)=\frac{5}{0}\quad\text{not allowed} \]
Picture it
Animation
Shows: Each line of the worked example "Guided try: another formula domain", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: All real inputs are allowed except negative two.
Anomaly
Predict first
A student writes this, and it looks reasonable:
Use an open circle at the boundary
It is wrong. Say what breaks — and say it before you turn the page.
Correct: This says the boundary value is not included, which contradicts the equality part.
This says the boundary value is not included, which contradicts the equality part.
Why: This says the boundary value is not included, which contradicts the equality part.
Trap
\[ x\le2 \]
Use an open circle at the boundary
Why: This says the boundary value is not included, which contradicts the equality part.
\[ \longleftarrow\!\!\!\circ\quad\text{at }2 \]
Check the boundary value
Why: The value two satisfies the inequality, so it must appear on the graph.
\[ 2\le2\checkmark \]
\[ x\le2 \]
Use a closed circle at the boundary
Why: The equality part includes the boundary value.
\[ \longleftarrow\!\!\!\bullet\quad\text{at }2 \]
Check the boundary value
Why: The graph includes two, matching the inequality.
\[ 2\le2\checkmark \]
Two truths and a lie
Sort into buckets
Some of these hold up and some are the exact mistakes this lesson is built to prevent. Sort them.
Estimation
Predict first
Your turn: work this on paper before you reveal the hint.
Commit before you compute: what does Guided try: evaluate with zero come out to? A rough magnitude and the right form is enough — the point is to have something concrete to be wrong about.
Correct: Check with an input-output pair
Why: A prediction you can defend turns the computation into a check rather than a leap of faith — and an answer that contradicts it is caught on the spot. The ordered pair for this evaluation is zero, two.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ q(x)=-3x^2+5x+2\qquad q(0) \]
Hint: zero often simplifies the rule
Why: Substitute zero into every variable position before doing arithmetic.
Substitute zero into the rule
Why: Every variable is replaced by the input.
\[ q(0)=-3(0)^2+5(0)+2 \]
Evaluate each term
Why: The variable terms become zero.
\[ q(0)=0+0+2 \]
State the output
Why: The input zero produces output two.
\[ q(0)=2 \]
Check with an input-output pair
Why: The ordered pair for this evaluation is zero, two.
| input | output |
|---|---|
| 0 | 2 |
Picture it
Animation
Shows: Each line of the worked example "Guided try: evaluate with zero", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: The ordered pair for this evaluation is zero, two.
Step zero
Discussion prompt
Independent try: mixed Week 2 practice — before any calculation: what is the plan? Name the moves in order, in plain English, without doing the arithmetic.
Hint: It starts with: Hint: these are three different jobs
Answer:
Worked example
Your turn: work this on paper before you reveal the hint.
\[ 2x-7\le1\qquad r(x)=\frac{4}{x-5}\qquad r(0) \]
Hint: these are three different jobs
Why: Solve the inequality, find the excluded input, then evaluate the function at zero.
Solve the inequality
Why: Add seven, then divide by two.
\[ 2x\le8\quad\Rightarrow\quad x\le4 \]
Find the excluded input
Why: The denominator cannot be zero.
\[ x-5=0\quad\Rightarrow\quad x=5 \]
Evaluate at zero
Why: Substitute zero into the rule.
\[ r(0)=\frac{4}{0-5}=-\frac{4}{5} \]
Check each result
Why: Four satisfies the inequality boundary, five breaks the function, and zero gives the listed output.
| task | check |
|---|---|
| inequality | 2(4)-7 = 1 |
| domain | x = 5 gives denominator 0 |
| evaluation | 4 / -5 = -4/5 |
Picture it
Animation
Shows: Each line of the worked example "Independent try: mixed Week 2 practice", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Four satisfies the inequality boundary, five breaks the function, and zero gives the listed output.
Concept
Homework should include solving, graphing, explaining, and correcting. The explanation is what turns a right answer into a stable skill.
| Day | Focus | Assignment |
|---|---|---|
| 8 | one- and two-step inequalities | 25 problems |
| 9 | negative multiply/divide | 20 problems plus 5 sign-flip checks |
| 10 | graphing inequalities | 20 number-line graphs |
| 11 | compound inequalities | 10 and, 10 or, 5 translations |
| 12 | function notation | 25 evaluations |
| 13 | domain and range | 20 questions |
| 14 | mixed quiz | 30 questions from Weeks 1 and 2 |
Trade off
Comparison matrix
From Daily practice map: every row here is a choice with a cost. Fill the Focus column, then say which row you would actually pick and what you give up for it.
| Day | Focus | Assignment |
|---|---|---|
| 8 | one- and two-step inequalities | 25 problems |
| 9 | negative multiply/divide | 20 problems plus 5 sign-flip checks |
| 10 | graphing inequalities | 20 number-line graphs |
| 11 | compound inequalities | 10 and, 10 or, 5 translations |
| 12 | function notation | 25 evaluations |
| 13 | domain and range | 20 questions |
| 14 | mixed quiz | 30 questions from Weeks 1 and 2 |
Pattern
1. Solve inequalities like equations until a negative scale appears
Why: Most inverse operations work the same way.
2. Reverse the inequality after multiplying or dividing by a negative
Why: Negative scaling reverses order on the number line.
3. Match endpoint symbols to open or closed circles
Why: Strict inequalities exclude endpoints; inclusive inequalities include them.
4. For compound statements, decide overlap or union
Why: And means both conditions; or means either condition.
5. For functions, substitute the input into the rule
Why: Function notation asks for an output, not multiplication.
Real world
Discussion prompt
Outside this lesson: where does Week 2: Inequalities, Graphing, and Functions actually turn up? Name one concrete situation — a job, a piece of software someone ships, a decision somebody has to make — and say which part of Week 2 master procedure is doing the work in it.
Hint: Vague is the failure mode here. "Engineering" is not a situation; "deciding whether this build is fast enough to ship" is.
Answer:
An hour-length bridge deck of 40 slides that fills a full tutoring hour. It covers solving inequalities, graphing them on a number line, reasoning about when the sign flips, compound inequalities, function notation, and domain and range, then moves through guided practice and independent practice, with traps and checks along the way.
Check
Solve first, then test one value from your answer side.
Check your understanding
Solve: -2x + 5 < 13
Answer: A
Why: Subtract 5 to get -2x < 8. Divide by -2 and reverse the inequality, giving x > -4.
Check
Think circle first, shading second.
Check your understanding
Which graph matches x >= -3?
Answer: A
Why: The equality part includes -3, so the endpoint is closed. Greater values are to the right, so shade right.
Elimination
Eliminate the wrong options
Which notation matches: at least 10 and less than 18?
3 of these 4 are wrong. Strike them one at a time, and say what rules each one out before you strike the next. The survivor is the answer.
Survives elimination: A
Why: At least 10 means 10 is included. Less than 18 means 18 is not included. The word and creates the overlap 10 <= t < 18.
Check
Decide whether the statement is overlap or union.
Check your understanding
Which notation matches: at least 10 and less than 18?
Answer: A
Why: At least 10 means 10 is included. Less than 18 means 18 is not included. The word and creates the overlap 10 <= t < 18.
Check
Substitute the input into every variable spot.
Check your understanding
If f(x) = 2x^2 - 3, what is f(-2)?
Answer: A
Why: Substitute -2 for x: f(-2) = 2(-2)^2 - 3. The square gives 4, so the output is 8 - 3 = 5.
Elimination
Eliminate the wrong options
What value is excluded from the domain of p(x) = 5 / (x + 2)?
3 of these 4 are wrong. Strike them one at a time, and say what rules each one out before you strike the next. The survivor is the answer.
Survives elimination: A
Why: The denominator cannot be zero. Set x + 2 = 0 and solve to get x = -2, so -2 is excluded.
Check
Find the input that would make the denominator zero.
Check your understanding
What value is excluded from the domain of p(x) = 5 / (x + 2)?
Answer: A
Why: The denominator cannot be zero. Set x + 2 = 0 and solve to get x = -2, so -2 is excluded.
Ranking
Put in order
Put the moves of Independent mini exit ticket into the order they have to happen.
Why: These are the moves of the worked example in the order it makes them, and each one is set up by the one before it. The first inequality divides by a negative number.
Worked example
Try all three before revealing the answers. Explain the graph or output out loud.
\[ -4x+1\ge9\qquad -2<z\le6\qquad h(x)=x^2-5,\ h(-3) \]
Hint: one problem needs the flip rule
Why: The first inequality divides by a negative number.
Solve the three prompts
Why: Compare only after attempting each one.
| Prompt | Answer |
|---|---|
| -4x + 1 >= 9 | x <= -2 |
| -2 < z <= 6 | open at -2, closed at 6, shade between |
| h(-3) | 4 |
Check each result
Why: Test one value for the inequality and substitute the function input into the rule.
| Prompt | Check |
|---|---|
| inequality | x = -3 works, x = -1 fails |
| compound | 0 works, -2 fails, 6 works |
| function | (-3)^2 - 5 = 4 |
Comparison
Comparison matrix
From Independent mini exit ticket: refill the Check column from what you know. The rest of the table is as it appeared.
| Prompt | Check |
|---|---|
| inequality | x = -3 works, x = -1 fails |
| compound | 0 works, -2 fails, 6 works |
| function | (-3)^2 - 5 = 4 |
Connect it up
Draw it
One page, no notation unless you need it: draw how these connect — Week 2 master procedure · How this hour will run · Equation answers versus inequality answers · Graphing inequality endpoints · The one special inequality rule. Put an arrow wherever one of them is what makes another possible, and label the arrow with why.
Recap
This hour makes solution sets concrete: solve carefully, reverse after negative scaling, graph endpoints correctly, and treat functions as input-output rules.
| Skill | Student can say |
|---|---|
| inequality solving | I know when the sign flips. |
| graphing | I choose endpoint and shading separately. |
| compound inequalities | I know whether to overlap or unite regions. |
| function notation | I substitute inputs into the rule. |
| domain/range | I can name allowed inputs and actual outputs. |
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