Week 1: Expressions, Equations, and Literal Equations

An hour-length bridge deck of 40 slides that fills a full tutoring hour. It covers terms and like terms, distribution, working with negative signs, multi-step equations, and literal equations, then moves through guided practice and independent practice, with traps and checks along the way.

Subject: Algebra 2 Readiness · 93 slides · symbolic lesson

Open the interactive version of this deck · Homework for this lesson

What this lesson covers

The lesson, slide by slide

1. Week 1 goals

Objectives

By the end of this hour you can:

1. Break expressions into terms, coefficients, variable parts, and constants.

2. Distribute positives and negatives one term at a time.

3. Combine like terms only after the terms truly match.

4. Solve equations by cleaning each side, undoing operations, and verifying.

5. Rearrange formulas by treating the target variable like the unknown.

2. How this hour will run

Concept

The hour is built in short loops: teacher model, guided attempt, independent attempt, then a correction note.

PartMinutesJob
warm-up0-10name terms and combine like terms
expressions10-25distribute, especially negatives
equations25-45clean sides, undo, verify
literal equations45-55solve formulas for a target
exit ticket55-60mixed independent check

3. Fill in: Minutes for How this hour will run

Comparison

Comparison matrix

From How this hour will run: refill the Minutes column from what you know. The rest of the table is as it appeared.

PartMinutesJob
warm-up0-10name terms and combine like terms
expressions10-25distribute, especially negatives
equations25-45clean sides, undo, verify
literal equations45-55solve formulas for a target
exit ticket55-60mixed independent check

4. Correction rule for every miss

Concept

A missed problem is not finished when the answer is copied. It is finished when the student can name the mistake and repair it.

Correction lineWhat the student writes
correct workthe full corrected solution
mistake nameone sentence naming the wrong move
prevention cueone phrase to remember next time

5. What each one costs: Correction rule for every miss

Trade off

Comparison matrix

From Correction rule for every miss: every row here is a choice with a cost. Fill the What the student writes column, then say which row you would actually pick and what you give up for it.

Correction lineWhat the student writes
correct workthe full corrected solution
mistake nameone sentence naming the wrong move
prevention cueone phrase to remember next time

6. First, sort the pieces

Concept

term — One signed piece of an expression. Terms are separated by plus or minus signs that are not inside parentheses.

coefficient — The numerical factor attached to a variable part.

constant — A term with no variable.

Sorting first slows the student down just enough to prevent unlike-term mistakes.

\[ 7x^2 - 4x + 9 - 3x^2 + 6 \]

7. Break it if you can: First, sort the pieces

Counterexample

Discussion prompt

Sorting first slows the student down just enough to prevent unlike-term mistakes.

That is stated as though it always holds. Do one of two things: produce a case where it fails, or say precisely what rules such a case out. "It just does" is not on the menu.

Hint: Hunt at the extremes first — zero, one, negative, empty, equal. If every extreme survives, the reason they survive is the proof.

8. What has to happen first: Model: label the expression

Ranking

Put in order

Put the moves of Model: label the expression into the order they have to happen.

  1. Circle each signed term
  2. Group terms with matching variable parts
  3. Combine each group
  4. Check by substituting one simple value

Why: These are the moves of the worked example in the order it makes them, and each one is set up by the one before it. The sign belongs to the term that follows it.

9. Model: label the expression

Worked example

Label the terms, variable parts, coefficients, and constants.

\[ 7x^2 - 4x + 9 - 3x^2 + 6 \]

Circle each signed term

Why: The sign belongs to the term that follows it.

termcoefficientvariable part
7x^27x^2
-4x-4x
99none
-3x^2-3x^2
66none

Group terms with matching variable parts

Why: Only exact matches can combine.

groupterms
x^2 terms7x^2 and -3x^2
x terms-4x
constants9 and 6

Combine each group

Why: Add the coefficients inside each group.

\[ 4x^2 - 4x + 15 \]

Check by substituting one simple value

Why: At one, both expressions give fifteen, so the simplified form is equivalent.

\[ 7-4+9-3+6=15\quad\text{and}\quad4-4+15=15\checkmark \]

10. Model: label the expression — line by line

Picture it

Animation

Shows: Each line of the worked example "Model: label the expression", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: At one, both expressions give fifteen, so the simplified form is equivalent.

11. Plan first: Guided try: sort before simplifying

Step zero

Discussion prompt

Guided try: sort before simplifying — before any calculation: what is the plan? Name the moves in order, in plain English, without doing the arithmetic.

Hint: It starts with: Hint: make three piles

Answer:

  1. Hint: make three piles
  2. Group matching variable parts
  3. Combine within each pile
  4. Check with one input

12. Guided try: sort before simplifying

Worked example

Your turn: work this on paper before you reveal the hint.

\[ 5x + 8 - 2x + 4x^2 - 3 \]

Hint: make three piles

Why: Use one pile for constants, one for first-power variable terms, and one for squared variable terms.

Group matching variable parts

Why: Squared terms, first-power terms, and constants are different types of pieces.

pileterms
squared4x^2
first-power5x and -2x
constant8 and -3

Combine within each pile

Why: Only coefficients in the same pile can be added.

\[ 4x^2 + 3x + 5 \]

Check with one input

Why: At two, the original and simplified expressions both give twenty-seven.

\[ 5(2)+8-2(2)+4(2)^2-3=27\quad\text{and}\quad4(2)^2+3(2)+5=27\checkmark \]

13. Guided try: sort before simplifying — line by line

Picture it

Animation

Shows: Each line of the worked example "Guided try: sort before simplifying", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: At two, the original and simplified expressions both give twenty-seven.

14. Like terms must match exactly

Concept

The variable part is the identity tag. If the identity tags differ, the terms cannot combine.

Can combine?Reason
3x and 2xsame variable part
3x and 2x^2different variable parts
5 and -9both constants
a and 4asame variable part

15. Which is which, by Reason

Discrimination

Sort into buckets

Sort these by Reason, from memory, without looking back at Like terms must match exactly. Telling them apart on the spot is the skill; the table is only where the answer happens to be written down.

same variable part
3x and 2x; a and 4a
different variable parts
3x and 2x^2
both constants
5 and -9
g1
Reason is "same variable part" for 3x and 2x, a and 4a — that is what the table on "Like terms must match exactly" records, and it is the single property separating this group from the rest.
g2
Reason is "different variable parts" for 3x and 2x^2 — that is what the table on "Like terms must match exactly" records, and it is the single property separating this group from the rest.
g3
Reason is "both constants" for 5 and -9 — that is what the table on "Like terms must match exactly" records, and it is the single property separating this group from the rest.

16. Model: combine in two passes

Worked example

Simplify:

\[ 6x - 4 + 3x^2 - 9x + 11 - x^2 \]

Rewrite with matching terms next to each other

Why: This is a sorting move, not a value-changing move.

\[ 3x^2 - x^2 + 6x - 9x - 4 + 11 \]

Combine squared terms

Why: The variable parts match.

\[ 2x^2 + 6x - 9x - 4 + 11 \]

Combine first-power terms and constants

Why: Each pile is handled separately.

\[ 2x^2 - 3x + 7 \]

Verify by testing one input

Why: At zero, both forms give seven; this quick check catches constant mistakes.

\[ -4+11=7\quad\text{and}\quad7=7\checkmark \]

17. Model: combine in two passes — line by line

Picture it

Animation

Shows: Each line of the worked example "Model: combine in two passes", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: At zero, both forms give seven; this quick check catches constant mistakes.

18. Guess the shape of the answer: Independent try: combine like terms

Estimation

Predict first

Your turn: work this on paper before you reveal the hint.

Commit before you compute: what does Independent try: combine like terms come out to? A rough magnitude and the right form is enough — the point is to have something concrete to be wrong about.

Correct: Combine each group

Why: A prediction you can defend turns the computation into a check rather than a leap of faith — and an answer that contradicts it is caught on the spot. Add coefficients and keep the matching variable part.

19. Independent try: combine like terms

Worked example

Your turn: work this on paper before you reveal the hint.

\[ 8x^2 - 5x + 4 - 3x^2 + 7x - 10 \]

Hint: sort before you calculate

Why: Do not combine first-power terms with squared terms.

Group the matching terms

Why: Terms with the same variable part go together.

groupterms
x^28x^2 and -3x^2
x-5x and 7x
constant4 and -10

Combine each group

Why: Add coefficients and keep the matching variable part.

\[ 5x^2 + 2x - 6 \]

Check with one input

Why: At one, both forms produce one.

\[ 8-5+4-3+7-10=1\quad\text{and}\quad5+2-6=1\checkmark \]

20. Independent try: combine like terms — line by line

Picture it

Animation

Shows: Each line of the worked example "Independent try: combine like terms", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: Add coefficients and keep the matching variable part.

21. Something is wrong here: unlike terms do not merge

Anomaly

Predict first

A student writes this, and it looks reasonable:

Add the coefficients and keep one variable

It is wrong. Say what breaks — and say it before you turn the page.

Correct: This ignores the different variable parts.

This ignores the different variable parts.

Why: This ignores the different variable parts.

22. Trap: unlike terms do not merge

Trap

The trap

\[ 3x + 2x^2 \]

Add the coefficients and keep one variable

Why: This ignores the different variable parts.

\[ 5x \]

Check with one input

Why: At two, the original gives fourteen, but the wrong simplification gives ten.

\[ 3(2)+2(2)^2=14\quad\text{but}\quad5(2)=10 \]

The fix

\[ 3x + 2x^2 \]

Leave unlike terms separate

Why: The variable parts do not match, so there is no combining move.

\[ 2x^2 + 3x \]

Check with the same input

Why: At two, the reordered expression still gives fourteen.

\[ 2(2)^2+3(2)=14\checkmark \]

23. Decode the notation: Trap: unlike terms do not merge

Notation

Annotate

From Trap: unlike terms do not merge — read this one piece at a time. What is each part doing?

On: \( 3(2)+2(2)^2=14\quad\text{but}\quad5(2)=10 \)

  • This ignores the different variable parts.
  • At two, the original gives fourteen, but the wrong simplification gives ten.
  • The variable parts do not match, so there is no combining move.

24. Distribution opens a package

Concept

A factor outside parentheses multiplies every term inside the package.

\[ a(b+c)=ab+ac \]

The most important tutoring move is to point at each inside term before multiplying.

25. By analogy: Distribution opens a package

Analogy

Discussion prompt

Explain Distribution opens a package by analogy to something with no Algebra 2 Readiness in it at all — a queue, a recipe, a map, a bank balance, whatever fits. Then say where your analogy breaks.

Hint: An analogy that never breaks is not an analogy, it is the same idea wearing a hat. Find the seam — that is the part that is actually new.

Answer:

A factor outside parentheses multiplies every term inside the package.

26. Model: distribute a positive factor

Worked example

Distribute and simplify:

\[ 3(2x - 5) + 4x \]

Multiply the outside factor by the first inside term

Why: Three groups of two variable terms make six variable terms.

\[ 6x - 15 + 4x \]

Multiply the outside factor by the second inside term

Why: The negative sign stays attached to the five.

\[ 6x - 15 + 4x \]

Combine like terms

Why: The variable terms match; the constant has no partner.

\[ 10x - 15 \]

Verify with one input

Why: At two, both expressions give five.

\[ 3(2(2)-5)+4(2)=5\quad\text{and}\quad10(2)-15=5\checkmark \]

27. Model: distribute a positive factor — line by line

Picture it

Animation

Shows: Each line of the worked example "Model: distribute a positive factor", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: The variable terms match; the constant has no partner.

28. Guided try: distribute positive

Worked example

Your turn: work this on paper before you reveal the hint.

\[ 4(x - 6) + 2x \]

Hint: there are two products inside the parentheses

Why: Multiply four by the variable term and by the constant term before combining.

Distribute four to both inside terms

Why: Both pieces inside the package get multiplied.

\[ 4x - 24 + 2x \]

Combine like terms

Why: Only the variable terms combine.

\[ 6x - 24 \]

Check with one input

Why: At five, both expressions give six.

\[ 4(5-6)+2(5)=6\quad\text{and}\quad6(5)-24=6\checkmark \]

29. Guided try: distribute positive — line by line

Picture it

Animation

Shows: Each line of the worked example "Guided try: distribute positive", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: Both pieces inside the package get multiplied.

30. A negative distributor changes every sign it touches

Concept

A minus outside parentheses is a multiplier. It does not merely change the first term.

\[ -1(a-b)=-a+b \]

Say this aloud: negative times positive is negative; negative times negative is positive.

31. Teach it back: A negative distributor changes every sign it touches

Explain it

Discussion prompt

Explain A negative distributor changes every sign it touches to a student a year behind you. No notation, no jargon they have not met — and it still has to be true.

Hint: If your explanation needs a symbol they have never seen, you are describing the notation rather than the idea.

Answer:

A minus outside parentheses is a multiplier. It does not merely change the first term.

32. Plan first: Model: simplify with a negative distributor

Step zero

Discussion prompt

Model: simplify with a negative distributor — before any calculation: what is the plan? Name the moves in order, in plain English, without doing the arithmetic.

Hint: It starts with: Name the outside multiplier

Answer:

  1. Name the outside multiplier
  2. Multiply the first inside term
  3. Multiply the second inside term
  4. Combine variable terms
  5. Combine constants
  6. Verify by testing one input

33. Model: simplify with a negative distributor

Worked example

Simplify:

\[ 4x - 3(2x - 5) + 7 \]

Name the outside multiplier

Why: The multiplier is negative three, not just three.

\[ -3(2x-5) \]

Multiply the first inside term

Why: Negative three times two variable terms gives negative six variable terms.

\[ 4x - 6x + 15 + 7 \]

Multiply the second inside term

Why: Negative three times negative five gives positive fifteen.

\[ 4x - 6x + 15 + 7 \]

Combine variable terms

Why: Four variable terms minus six variable terms leaves negative two variable terms.

\[ -2x + 15 + 7 \]

Combine constants

Why: Fifteen plus seven is twenty-two.

\[ -2x + 22 \]

Verify by testing one input

Why: At three, both forms give sixteen.

\[ 4(3)-3(2(3)-5)+7=16\quad\text{and}\quad-2(3)+22=16\checkmark \]

34. Model: simplify with a negative distributor — line by line

Picture it

Animation

Shows: Each line of the worked example "Model: simplify with a negative distributor", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: Four variable terms minus six variable terms leaves negative two variable terms.

35. Guided try: parentheses subtraction

Worked example

Your turn: work this on paper before you reveal the hint.

\[ 2x - (5x - 7) \]

Hint: rewrite the subtraction as negative one times the package

Why: The minus outside the parentheses must touch both inside terms.

Distribute negative one to both inside terms

Why: The first term changes negative, and the negative constant changes positive.

\[ 2x - 5x + 7 \]

Combine the variable terms

Why: Two variable terms minus five variable terms leaves negative three variable terms.

\[ -3x + 7 \]

Check with one input

Why: At four, both expressions give negative five.

\[ 2(4)-(5(4)-7)=-5\quad\text{and}\quad-3(4)+7=-5\checkmark \]

36. Guided try: parentheses subtraction — line by line

Picture it

Animation

Shows: Each line of the worked example "Guided try: parentheses subtraction", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: At four, both expressions give negative five.

37. Something is wrong here: the negative does not stop halfway

Anomaly

Predict first

A student writes this, and it looks reasonable:

Multiply the first term, then keep the second sign unchanged

It is wrong. Say what breaks — and say it before you turn the page.

Correct: This misses the second multiplication by the outside negative.

This misses the second multiplication by the outside negative.

Why: This misses the second multiplication by the outside negative.

38. Trap: the negative does not stop halfway

Trap

The trap

\[ -3(x - 4) \]

Multiply the first term, then keep the second sign unchanged

Why: This misses the second multiplication by the outside negative.

\[ -3x - 12 \]

Check with one value

Why: At one, the original gives nine, but the wrong expression gives negative fifteen.

\[ -3(1-4)=9\quad\text{but}\quad-3(1)-12=-15 \]

The fix

\[ -3(x - 4) \]

Multiply both terms by the outside negative

Why: A negative times a negative constant becomes positive.

\[ -3x + 12 \]

Check with the same value

Why: At one, both the original and simplified expressions give nine.

\[ -3(1-4)=9\quad\text{and}\quad-3(1)+12=9\checkmark \]

39. Decode the notation: Trap: the negative does not stop halfway

Notation

Annotate

From Trap: the negative does not stop halfway — read this one piece at a time. What is each part doing?

On: \( -3(1-4)=9\quad\text{and}\quad-3(1)+12=9\checkmark \)

  • This misses the second multiplication by the outside negative.
  • At one, the original gives nine, but the wrong expression gives negative fifteen.
  • A negative times a negative constant becomes positive.

40. Equations stay balanced

Concept

Solving is a sequence of legal moves that keep both sides equal.

\[ x+7=12 \]

Every move must happen to both sides, and the final answer must work in the original equation.

41. Teach it back: Equations stay balanced

Explain it

Discussion prompt

Explain Equations stay balanced to a student a year behind you. No notation, no jargon they have not met — and it still has to be true.

Hint: If your explanation needs a symbol they have never seen, you are describing the notation rather than the idea.

Answer:

Solving is a sequence of legal moves that keep both sides equal.

42. Complete the line: Model: one-step equation

Fill the middle

Fill in the blanks

From Model: one-step equation — finish the line. Write what belongs on the right of the equals sign before you look.

x+7-7 = 12-7

Why: Producing the right-hand side unprompted is the difference between recognising this line and being able to use it. Addition is undone by subtraction, and both sides must change together.

43. Model: one-step equation

Worked example

Solve:

\[ x+7=12 \]

Identify what is attached to the variable

Why: Seven is being added to the variable.

\[ x+7=12 \]

Use the inverse operation on both sides

Why: Addition is undone by subtraction, and both sides must change together.

\[ x+7-7=12-7 \]

Simplify both sides

Why: The variable is now alone.

\[ x=5 \]

Verify in the original equation

Why: Five plus seven equals twelve.

\[ 5+7=12\checkmark \]

44. Model: one-step equation — line by line

Picture it

Animation

Shows: Each line of the worked example "Model: one-step equation", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: Addition is undone by subtraction, and both sides must change together.

45. Guess the shape of the answer: Independent try: one-step equation

Estimation

Predict first

Your turn: work this on paper before you reveal the hint.

Commit before you compute: what does Independent try: one-step equation come out to? A rough magnitude and the right form is enough — the point is to have something concrete to be wrong about.

Correct: Add nine to both sides

Why: A prediction you can defend turns the computation into a check rather than a leap of faith — and an answer that contradicts it is caught on the spot. Adding nine undoes subtracting nine while keeping the equation balanced.

46. Independent try: one-step equation

Worked example

Your turn: work this on paper before you reveal the hint.

\[ x - 9 = -2 \]

Hint: undo subtraction

Why: Ask what operation would remove a minus nine.

Add nine to both sides

Why: Adding nine undoes subtracting nine while keeping the equation balanced.

\[ x=7 \]

Check in the original equation

Why: Seven minus nine equals negative two.

\[ 7-9=-2\checkmark \]

47. Independent try: one-step equation — line by line

Picture it

Animation

Shows: Each line of the worked example "Independent try: one-step equation", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: Adding nine undoes subtracting nine while keeping the equation balanced.

48. What has to happen first: Model: two-step equation

Ranking

Put in order

Put the moves of Model: two-step equation into the order they have to happen.

  1. Undo the addition or subtraction first
  2. Undo the coefficient second
  3. State the answer in test-answer form
  4. Verify in the original equation

Why: These are the moves of the worked example in the order it makes them, and each one is set up by the one before it. The minus four was applied after the multiplication by three.

49. Model: two-step equation

Worked example

Solve:

\[ 3x - 4 = 11 \]

Undo the addition or subtraction first

Why: The minus four was applied after the multiplication by three.

\[ 3x=15 \]

Undo the coefficient second

Why: Divide both sides by three.

\[ x=5 \]

State the answer in test-answer form

Why: The variable is alone, so the answer is ready to check.

\[ x=5 \]

Verify in the original equation

Why: Three times five minus four equals eleven.

\[ 3(5)-4=11\checkmark \]

50. Model: two-step equation — line by line

Picture it

Animation

Shows: Each line of the worked example "Model: two-step equation", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: Three times five minus four equals eleven.

51. State the rule before it runs: Guided try: two-step equation

Hypothesis

Predict first

Guided try: two-step equation is about to be worked. State your hypothesis first: which rule or definition decides this one, and what is the first move it forces? Then watch whether the example agrees with you.

Correct: Hint: clear the constant first

Why: Undo plus six before dividing by the coefficient.

A hypothesis you wrote down is falsifiable; a vague sense of how it will go is not. If the example opens somewhere else, that gap is the thing worth chasing.

52. Guided try: two-step equation

Worked example

Your turn: work this on paper before you reveal the hint.

\[ 4x + 6 = -10 \]

Hint: clear the constant first

Why: Undo plus six before dividing by the coefficient.

Subtract six from both sides

Why: This leaves the variable term alone on the left.

\[ 4x=-16 \]

Divide by four

Why: The coefficient is undone last.

\[ x=-4 \]

Check in the original equation

Why: Four times negative four plus six equals negative ten.

\[ 4(-4)+6=-10\checkmark \]

53. Guided try: two-step equation — line by line

Picture it

Animation

Shows: Each line of the worked example "Guided try: two-step equation", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: Four times negative four plus six equals negative ten.

54. Multi-step equations: clean sides, then undo

Concept

When an equation has parentheses or like terms, do not move terms immediately. First simplify each side on its own.

PhaseQuestion
clean sidesCan either side be simplified without crossing the equals sign?
collectWhere should the variable terms live?
undoWhat inverse operation isolates the variable?
verifyDoes the answer satisfy the original?

55. By analogy: Multi-step equations: clean sides, then undo

Analogy

Discussion prompt

Explain Multi-step equations: clean sides, then undo by analogy to something with no Algebra 2 Readiness in it at all — a queue, a recipe, a map, a bank balance, whatever fits. Then say where your analogy breaks.

Hint: An analogy that never breaks is not an analogy, it is the same idea wearing a hat. Find the seam — that is the part that is actually new.

Answer:

When an equation has parentheses or like terms, do not move terms immediately. First simplify each side on its own.

56. Model: clean sides, then solve

Worked example

Solve:

\[ 2(3x - 4)=5x+9 \]

Distribute on the left side

Why: Clean the side with parentheses before moving terms.

\[ 6x - 8 = 5x + 9 \]

Subtract the smaller variable term from both sides

Why: This keeps the remaining coefficient positive.

\[ x - 8 = 9 \]

Add eight to both sides

Why: Undo the subtraction around the variable.

\[ x=17 \]

Verify by substituting seventeen into the original equation

Why: Both original sides become ninety-four.

\[ 2(3(17)-4)=94\quad\text{and}\quad5(17)+9=94\checkmark \]

57. Model: clean sides, then solve — line by line

Picture it

Animation

Shows: Each line of the worked example "Model: clean sides, then solve", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: Undo the subtraction around the variable.

58. Plan first: Guided try: equation with a negative distributor

Step zero

Discussion prompt

Guided try: equation with a negative distributor — before any calculation: what is the plan? Name the moves in order, in plain English, without doing the arithmetic.

Hint: It starts with: Hint: distribute before solving

Answer:

  1. Hint: distribute before solving
  2. Distribute negative three
  3. Combine constants on the left
  4. Subtract eleven from both sides
  5. Divide by negative three
  6. Check in the original equation

59. Guided try: equation with a negative distributor

Worked example

Your turn: work this on paper before you reveal the hint.

\[ -3(x - 2) + 5 = 14 \]

Hint: distribute before solving

Why: The outside negative multiplies both terms inside the parentheses.

Distribute negative three

Why: Negative three times negative two becomes positive six.

\[ -3x + 6 + 5 = 14 \]

Combine constants on the left

Why: The left side can be cleaned before any balance move.

\[ -3x + 11 = 14 \]

Subtract eleven from both sides

Why: This isolates the variable term.

\[ -3x=3 \]

Divide by negative three

Why: The coefficient is undone last.

\[ x=-1 \]

Check in the original equation

Why: Substituting negative one gives fourteen.

\[ -3((-1)-2)+5=14\checkmark \]

60. Guided try: equation with a negative distributor — line by line

Picture it

Animation

Shows: Each line of the worked example "Guided try: equation with a negative distributor", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: Substituting negative one gives fourteen.

61. Something is wrong here: solving before cleaning

Anomaly

Predict first

A student writes this, and it looks reasonable:

Subtract five variable terms before distributing

It is wrong. Say what breaks — and say it before you turn the page.

Correct: The terms are not ready to combine because one side still has parentheses.

The terms are not ready to combine because one side still has parentheses.

Why: The terms are not ready to combine because one side still has parentheses.

62. Trap: solving before cleaning

Trap

The trap

\[ 2(3x - 4)=5x+9 \]

Subtract five variable terms before distributing

Why: The terms are not ready to combine because one side still has parentheses.

\[ 2(3x-4)-5x=9 \]

Lose track of what the left side means

Why: The equation becomes harder and sign errors multiply.

\[ 6x-8-5x=9 \]

The fix

\[ 2(3x - 4)=5x+9 \]

Distribute first

Why: Cleaning each side makes the next balance move obvious.

\[ 6x-8=5x+9 \]

Then collect variable terms

Why: Now subtracting five variable terms is a clean balance move.

\[ x-8=9\checkmark \]

63. Which of these survive contact with Week 1: Expressions, Equations, and Literal…?

Two truths and a lie

Sort into buckets

Some of these hold up and some are the exact mistakes this lesson is built to prevent. Sort them.

Holds up
The hour is built in short loops: teacher model, guided attempt, independent attempt, then a correction note.; A missed problem is not finished when the answer is copied. It is finished when the student can name the mistake and repair it.; Sorting first slows the student down just enough to prevent unlike-term mistakes.
Breaks
Add the coefficients and keep one variable; Multiply the first term, then keep the second sign unchanged
sound
These are stated as this lesson states them — each one survives the edge cases Week 1: Expressions, Equations, and Literal Equations puts it through.
flawed
Each of these is lifted from a trap in this deck: reasonable-sounding, and wrong in a way that only shows up once you rely on it.

64. Variables on both sides are still balance problems

Concept

Variable terms are quantities too. You can add or subtract them from both sides just like constants.

\[ 5x - 2 = 3x + 8 \]

Choose the move that keeps the remaining coefficient positive when possible.

65. Break it if you can: Variables on both sides are still balance problems

Counterexample

Discussion prompt

Variable terms are quantities too. You can add or subtract them from both sides just like constants.

That is stated as though it always holds. Do one of two things: produce a case where it fails, or say precisely what rules such a case out. "It just does" is not on the menu.

Hint: Hunt at the extremes first — zero, one, negative, empty, equal. If every extreme survives, the reason they survive is the proof.

Answer:

Choose the move that keeps the remaining coefficient positive when possible.

66. Complete the line: Model: variable on both sides

Fill the middle

Fill in the blanks

From Model: variable on both sides — finish the line. Write what belongs on the right of the equals sign before you look.

5x - 2 = 3x + 8

Why: Producing the right-hand side unprompted is the difference between recognising this line and being able to use it. Collect variables on the side with more variable terms.

67. Model: variable on both sides

Worked example

Solve:

\[ 5x - 2 = 3x + 8 \]

Subtract three variable terms from both sides

Why: Collect variables on the side with more variable terms.

\[ 2x - 2 = 8 \]

Add two to both sides

Why: Clear the constant from the variable side.

\[ 2x=10 \]

Divide by two

Why: Undo the coefficient.

\[ x=5 \]

Verify in both original sides

Why: Both sides become twenty-three.

\[ 5(5)-2=23\quad\text{and}\quad3(5)+8=23\checkmark \]

68. Model: variable on both sides — line by line

Picture it

Animation

Shows: Each line of the worked example "Model: variable on both sides", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: Clear the constant from the variable side.

69. Independent try: variable on both sides

Worked example

Your turn: work this on paper before you reveal the hint.

\[ 7x + 4 = 2x - 11 \]

Hint: keep the variable coefficient positive

Why: Move the smaller variable term to the other side.

Subtract two variable terms from both sides

Why: This leaves five variable terms on the left.

\[ 5x+4=-11 \]

Subtract four from both sides

Why: Clear the constant from the variable side.

\[ 5x=-15 \]

Divide by five

Why: The coefficient is undone last.

\[ x=-3 \]

Check in the original equation

Why: Both sides become negative seventeen.

\[ 7(-3)+4=-17\quad\text{and}\quad2(-3)-11=-17\checkmark \]

70. Independent try: variable on both sides — line by line

Picture it

Animation

Shows: Each line of the worked example "Independent try: variable on both sides", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: Clear the constant from the variable side.

71. Literal equations: choose the target

Concept

A literal equation has several letters, but only one target variable. Treat every other letter as a known quantity.

\[ A=\frac{1}{2}bh \]

target variable — The variable that must be alone at the end.

72. Term to definition: Week 1: Expressions, Equations, and Literal Equations

Matching

Match the pairs

Match each term to the definition this lesson gave it — not the one you would guess from the word.

  • t1. term
  • t2. coefficient
  • t3. target variable
  • d1. One signed piece of an expression. Terms are separated by plus or minus signs that are not inside parentheses.
  • d2. The numerical factor attached to a variable part.
  • d3. The variable that must be alone at the end.

Why: These are the working definitions of term, coefficient, target variable as Week 1: Expressions, Equations, and Literal Equations uses them. Pairing them correctly is the test of whether you could state each one with the slide switched off.

73. Complete the line: Model: solve a formula for height

Fill the middle

Fill in the blanks

From Model: solve a formula for height — finish the line. Write what belongs on the right of the equals sign before you look.

\fracA\checkmark___b\left(\frac______\right) = ___

Why: Producing the right-hand side unprompted is the difference between recognising this line and being able to use it. The target is multiplied by b and by one half.

74. Model: solve a formula for height

Worked example

Solve for the target variable:

\[ A=\frac{1}{2}bh\qquad\text{target: }h \]

Identify what is attached to the target

Why: The target is multiplied by b and by one half.

\[ A=\frac{1}{2}bh \]

Multiply both sides by two

Why: This removes the factor of one half.

\[ 2A=bh \]

Divide both sides by b

Why: This leaves the target variable alone.

\[ h=\frac{2A}{b} \]

Verify by substituting the rearranged expression

Why: The original formula simplifies back to A.

\[ \frac{1}{2}b\left(\frac{2A}{b}\right)=A\checkmark \]

75. Model: solve a formula for height — line by line

Picture it

Animation

Shows: Each line of the worked example "Model: solve a formula for height", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: The original formula simplifies back to A.

76. Guess the shape of the answer: Guided try: solve slope-intercept form for…

Estimation

Predict first

Your turn: work this on paper before you reveal the hint.

Commit before you compute: what does Guided try: solve slope-intercept form for the input come out to? A rough magnitude and the right form is enough — the point is to have something concrete to be wrong about.

Correct: Divide both sides by m

Why: A prediction you can defend turns the computation into a check rather than a leap of faith — and an answer that contradicts it is caught on the spot. This removes the coefficient attached to the target.

77. Guided try: solve slope-intercept form for the input

Worked example

Your turn: work this on paper before you reveal the hint.

\[ y=mx+b\qquad\text{target: }x \]

Hint: remove the added constant before dividing

Why: Treat m and b like known numbers while isolating the target.

Subtract b from both sides

Why: This clears the added constant.

\[ y-b=mx \]

Divide both sides by m

Why: This removes the coefficient attached to the target.

\[ x=\frac{y-b}{m} \]

Check by substituting the expression back

Why: The right side simplifies to y.

\[ m\left(\frac{y-b}{m}\right)+b=y-b+b=y\checkmark \]

78. Guided try: solve slope-intercept form for the input — line by line

Picture it

Animation

Shows: Each line of the worked example "Guided try: solve slope-intercept form for the input", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: This removes the coefficient attached to the target.

79. Plan first: Independent try: solve a perimeter formula

Step zero

Discussion prompt

Independent try: solve a perimeter formula — before any calculation: what is the plan? Name the moves in order, in plain English, without doing the arithmetic.

Hint: It starts with: Hint: clear the term that does not contain the target

Answer:

  1. Hint: clear the term that does not contain the target
  2. Subtract two lengths from both sides
  3. Divide both sides by two
  4. Check by substituting the expression back

80. Independent try: solve a perimeter formula

Worked example

Your turn: work this on paper before you reveal the hint.

\[ P=2l+2w\qquad\text{target: }w \]

Hint: clear the term that does not contain the target

Why: The target term is two times width.

Subtract two lengths from both sides

Why: This leaves the target term on the right.

\[ P-2l=2w \]

Divide both sides by two

Why: This leaves the target variable alone.

\[ w=\frac{P-2l}{2} \]

Check by substituting the expression back

Why: The formula simplifies back to P.

\[ 2l+2\left(\frac{P-2l}{2}\right)=2l+P-2l=P\checkmark \]

81. Independent try: solve a perimeter formula — line by line

Picture it

Animation

Shows: Each line of the worked example "Independent try: solve a perimeter formula", appearing one at a time.

The same working the example does, in the order a tutor would write it.

Takeaway: This leaves the target term on the right.

82. Daily practice map

Concept

Use this map after the tutoring hour. The daily homework should feel familiar because the deck already rehearsed the moves.

DayFocusAssignment
1combine like terms25 problems, at least 10 with negatives
2distribute25 problems, including parentheses subtraction
3mixed simplifying20 problems plus 5 find-the-error problems
4multi-step equations20 problems with inverse operations shown
5literal equations15 formula rearrangements
6mixed quiz25 questions from Week 1
7correctionsredo misses, then 10 fresh mixed problems

83. What each one costs: Daily practice map

Trade off

Comparison matrix

From Daily practice map: every row here is a choice with a cost. Fill the Assignment column, then say which row you would actually pick and what you give up for it.

DayFocusAssignment
1combine like terms25 problems, at least 10 with negatives
2distribute25 problems, including parentheses subtraction
3mixed simplifying20 problems plus 5 find-the-error problems
4multi-step equations20 problems with inverse operations shown
5literal equations15 formula rearrangements
6mixed quiz25 questions from Week 1
7correctionsredo misses, then 10 fresh mixed problems

84. Week 1 master procedure

Pattern

1. Sort terms before calculating

Why: This prevents unlike terms from being combined.

2. Distribute to every term inside parentheses

Why: A factor outside the package touches every inside term.

3. Clean each side before solving

Why: Distribution and like-term combining happen before balance moves.

4. Undo operations on both sides

Why: Equations stay true only when both sides change together.

5. Verify in the original problem

Why: Original-problem verification catches sign errors and skipped steps.

85. Where this shows up: Week 1: Expressions, Equations, and Literal…

Real world

Discussion prompt

Outside this lesson: where does Week 1: Expressions, Equations, and Literal Equations actually turn up? Name one concrete situation — a job, a piece of software someone ships, a decision somebody has to make — and say which part of Week 1 master procedure is doing the work in it.

Hint: Vague is the failure mode here. "Engineering" is not a situation; "deciding whether this build is fast enough to ship" is.

Answer:

An hour-length bridge deck of 40 slides that fills a full tutoring hour. It covers terms and like terms, distribution, working with negative signs, multi-step equations, and literal equations, then moves through guided practice and independent practice, with traps and checks along the way.

86. Check 1: simplify

Check

Work it fully on paper first. Then choose the simplified form.

Check your understanding

Simplify: 4x - 3(2x - 5) + 7

  • A. -2x + 22 (correct)
  • B. -2x - 8
  • C. 10x - 8
  • D. -2x + 8

Answer: A

Why: Distribute the negative three to both inside terms: 4x - 6x + 15 + 7. Then combine like terms to get -2x + 22.

Why B tempts people
This distributes -3 as -6x - 15. The second product should be positive because a negative times a negative is positive.
Why C tempts people
This treats the outside -3 as if it adds 6x and subtracts 15. The multiplier is negative three.
Why D tempts people
This gets the variable term right but loses part of the constants. The constants are 15 and 7, which make 22.

87. Check 2: solve an equation

Check

Clean the side with parentheses before moving terms.

Check your understanding

Solve: 2(3x - 4) = 5x + 9

  • A. x = 17 (correct)
  • B. x = -17
  • C. x = 1
  • D. x = 9

Answer: A

Why: Distribute first: 6x - 8 = 5x + 9. Subtract 5x from both sides to get x - 8 = 9, then add 8. The solution is x = 17.

Why B tempts people
This usually comes from subtracting 9 instead of adding 8 after x - 8 = 9.
Why C tempts people
This stops after comparing coefficients. The constants still determine the value of x.
Why D tempts people
This reports the right-side constant after collecting variable terms, but x - 8 = 9 still needs one more step.

88. Check 3: literal equation

Check

Treat every non-target letter like a known quantity.

Check your understanding

Solve A = (1/2)bh for h.

  • A. h = 2A / b (correct)
  • B. h = A / (2b)
  • C. h = 2Ab
  • D. h = A - (1/2)b

Answer: A

Why: Multiply both sides by 2 to get 2A = bh. Then divide both sides by b to get h = 2A / b.

Why B tempts people
This divides by 2 instead of multiplying by 2. The factor one half must be undone by multiplying by 2.
Why C tempts people
This multiplies by b instead of dividing by b. The target is already multiplied by b.
Why D tempts people
This treats multiplication as subtraction. Literal equations still use inverse operations.

89. What has to happen first: Independent mini exit ticket

Ranking

Put in order

Put the moves of Independent mini exit ticket into the order they have to happen.

  1. Hint: use the Week 1 procedure
  2. Solve the three problems
  3. Check each answer

Why: These are the moves of the worked example in the order it makes them, and each one is set up by the one before it. Sort, distribute, clean, undo, and verify.

90. Independent mini exit ticket

Worked example

Try all three without revealing the answers. Write one correction sentence for any miss.

ProblemTask
1Simplify the expression.
2Solve the equation.
3Solve the formula for the target.

\[ 3x-(2x-9)+5\qquad4(x-2)=2x+10\qquad C=\frac{5}{9}(F-32)\text{ for }F \]

Hint: use the Week 1 procedure

Why: Sort, distribute, clean, undo, and verify.

Solve the three problems

Why: Compare your work to the answer forms only after you have attempted all three.

ProblemAnswer
1x + 14
2x = 9
3F = 9C / 5 + 32

Check each answer

Why: Substitute a simple value or the solved expression back into the original to confirm the result.

ProblemCheck
1try x = 1; both forms give 15
24(9 - 2) = 28 and 2(9) + 10 = 28
3substitution simplifies back to C

91. Fill in: Task for Independent mini exit ticket

Comparison

Comparison matrix

From Independent mini exit ticket: refill the Task column from what you know. The rest of the table is as it appeared.

ProblemTask
1Simplify the expression.
2Solve the equation.
3Solve the formula for the target.

92. Connect it up: Week 1: Expressions, Equations, and Literal Equations

Connect it up

Draw it

One page, no notation unless you need it: draw how these connect — Week 1 master procedure · How this hour will run · Correction rule for every miss · First, sort the pieces · Like terms must match exactly. Put an arrow wherever one of them is what makes another possible, and label the arrow with why.

93. Week 1 bridge built

Recap

This hour gives the student a repeatable algebra routine: sort terms, distribute carefully, combine only true like terms, solve by legal balance moves, and verify in the original.

SkillStudent can say
termsI know what pieces can combine.
distributionThe outside factor touches every inside term.
equationsI clean sides first, then undo.
literal equationsI isolate the target variable.
correctionsI can name the exact mistake.

Sources

  1. OpenStax Elementary Algebra 2e, Chapters 2 and 4 — OpenStax, Rice University, 2020. CC BY 4.0.
  2. OpenStax Intermediate Algebra 2e, Chapter 2 — OpenStax, Rice University, 2020. CC BY 4.0.

Want this taught 1-on-1? Alexander tutors Algebra 2 Readiness — $55/session, free consultation.

Book on Wyzant · Text (657) 465-8108