An hour-length bridge deck of 40 slides that fills a full tutoring hour. It covers terms and like terms, distribution, working with negative signs, multi-step equations, and literal equations, then moves through guided practice and independent practice, with traps and checks along the way.
Subject: Algebra 2 Readiness · 93 slides · symbolic lesson
Open the interactive version of this deck · Homework for this lesson
Objectives
By the end of this hour you can:
1. Break expressions into terms, coefficients, variable parts, and constants.
2. Distribute positives and negatives one term at a time.
3. Combine like terms only after the terms truly match.
4. Solve equations by cleaning each side, undoing operations, and verifying.
5. Rearrange formulas by treating the target variable like the unknown.
Concept
The hour is built in short loops: teacher model, guided attempt, independent attempt, then a correction note.
| Part | Minutes | Job |
|---|---|---|
| warm-up | 0-10 | name terms and combine like terms |
| expressions | 10-25 | distribute, especially negatives |
| equations | 25-45 | clean sides, undo, verify |
| literal equations | 45-55 | solve formulas for a target |
| exit ticket | 55-60 | mixed independent check |
Comparison
Comparison matrix
From How this hour will run: refill the Minutes column from what you know. The rest of the table is as it appeared.
| Part | Minutes | Job |
|---|---|---|
| warm-up | 0-10 | name terms and combine like terms |
| expressions | 10-25 | distribute, especially negatives |
| equations | 25-45 | clean sides, undo, verify |
| literal equations | 45-55 | solve formulas for a target |
| exit ticket | 55-60 | mixed independent check |
Concept
A missed problem is not finished when the answer is copied. It is finished when the student can name the mistake and repair it.
| Correction line | What the student writes |
|---|---|
| correct work | the full corrected solution |
| mistake name | one sentence naming the wrong move |
| prevention cue | one phrase to remember next time |
Trade off
Comparison matrix
From Correction rule for every miss: every row here is a choice with a cost. Fill the What the student writes column, then say which row you would actually pick and what you give up for it.
| Correction line | What the student writes |
|---|---|
| correct work | the full corrected solution |
| mistake name | one sentence naming the wrong move |
| prevention cue | one phrase to remember next time |
Concept
term — One signed piece of an expression. Terms are separated by plus or minus signs that are not inside parentheses.
coefficient — The numerical factor attached to a variable part.
constant — A term with no variable.
Sorting first slows the student down just enough to prevent unlike-term mistakes.
\[ 7x^2 - 4x + 9 - 3x^2 + 6 \]
Counterexample
Discussion prompt
Sorting first slows the student down just enough to prevent unlike-term mistakes.
That is stated as though it always holds. Do one of two things: produce a case where it fails, or say precisely what rules such a case out. "It just does" is not on the menu.
Hint: Hunt at the extremes first — zero, one, negative, empty, equal. If every extreme survives, the reason they survive is the proof.
Ranking
Put in order
Put the moves of Model: label the expression into the order they have to happen.
Why: These are the moves of the worked example in the order it makes them, and each one is set up by the one before it. The sign belongs to the term that follows it.
Worked example
Label the terms, variable parts, coefficients, and constants.
\[ 7x^2 - 4x + 9 - 3x^2 + 6 \]
Circle each signed term
Why: The sign belongs to the term that follows it.
| term | coefficient | variable part |
|---|---|---|
| 7x^2 | 7 | x^2 |
| -4x | -4 | x |
| 9 | 9 | none |
| -3x^2 | -3 | x^2 |
| 6 | 6 | none |
Group terms with matching variable parts
Why: Only exact matches can combine.
| group | terms |
|---|---|
| x^2 terms | 7x^2 and -3x^2 |
| x terms | -4x |
| constants | 9 and 6 |
Combine each group
Why: Add the coefficients inside each group.
\[ 4x^2 - 4x + 15 \]
Check by substituting one simple value
Why: At one, both expressions give fifteen, so the simplified form is equivalent.
\[ 7-4+9-3+6=15\quad\text{and}\quad4-4+15=15\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Model: label the expression", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: At one, both expressions give fifteen, so the simplified form is equivalent.
Step zero
Discussion prompt
Guided try: sort before simplifying — before any calculation: what is the plan? Name the moves in order, in plain English, without doing the arithmetic.
Hint: It starts with: Hint: make three piles
Answer:
Worked example
Your turn: work this on paper before you reveal the hint.
\[ 5x + 8 - 2x + 4x^2 - 3 \]
Hint: make three piles
Why: Use one pile for constants, one for first-power variable terms, and one for squared variable terms.
Group matching variable parts
Why: Squared terms, first-power terms, and constants are different types of pieces.
| pile | terms |
|---|---|
| squared | 4x^2 |
| first-power | 5x and -2x |
| constant | 8 and -3 |
Combine within each pile
Why: Only coefficients in the same pile can be added.
\[ 4x^2 + 3x + 5 \]
Check with one input
Why: At two, the original and simplified expressions both give twenty-seven.
\[ 5(2)+8-2(2)+4(2)^2-3=27\quad\text{and}\quad4(2)^2+3(2)+5=27\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Guided try: sort before simplifying", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: At two, the original and simplified expressions both give twenty-seven.
Concept
The variable part is the identity tag. If the identity tags differ, the terms cannot combine.
| Can combine? | Reason |
|---|---|
| 3x and 2x | same variable part |
| 3x and 2x^2 | different variable parts |
| 5 and -9 | both constants |
| a and 4a | same variable part |
Discrimination
Sort into buckets
Sort these by Reason, from memory, without looking back at Like terms must match exactly. Telling them apart on the spot is the skill; the table is only where the answer happens to be written down.
Worked example
Simplify:
\[ 6x - 4 + 3x^2 - 9x + 11 - x^2 \]
Rewrite with matching terms next to each other
Why: This is a sorting move, not a value-changing move.
\[ 3x^2 - x^2 + 6x - 9x - 4 + 11 \]
Combine squared terms
Why: The variable parts match.
\[ 2x^2 + 6x - 9x - 4 + 11 \]
Combine first-power terms and constants
Why: Each pile is handled separately.
\[ 2x^2 - 3x + 7 \]
Verify by testing one input
Why: At zero, both forms give seven; this quick check catches constant mistakes.
\[ -4+11=7\quad\text{and}\quad7=7\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Model: combine in two passes", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: At zero, both forms give seven; this quick check catches constant mistakes.
Estimation
Predict first
Your turn: work this on paper before you reveal the hint.
Commit before you compute: what does Independent try: combine like terms come out to? A rough magnitude and the right form is enough — the point is to have something concrete to be wrong about.
Correct: Combine each group
Why: A prediction you can defend turns the computation into a check rather than a leap of faith — and an answer that contradicts it is caught on the spot. Add coefficients and keep the matching variable part.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ 8x^2 - 5x + 4 - 3x^2 + 7x - 10 \]
Hint: sort before you calculate
Why: Do not combine first-power terms with squared terms.
Group the matching terms
Why: Terms with the same variable part go together.
| group | terms |
|---|---|
| x^2 | 8x^2 and -3x^2 |
| x | -5x and 7x |
| constant | 4 and -10 |
Combine each group
Why: Add coefficients and keep the matching variable part.
\[ 5x^2 + 2x - 6 \]
Check with one input
Why: At one, both forms produce one.
\[ 8-5+4-3+7-10=1\quad\text{and}\quad5+2-6=1\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Independent try: combine like terms", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Add coefficients and keep the matching variable part.
Anomaly
Predict first
A student writes this, and it looks reasonable:
Add the coefficients and keep one variable
It is wrong. Say what breaks — and say it before you turn the page.
Correct: This ignores the different variable parts.
This ignores the different variable parts.
Why: This ignores the different variable parts.
Trap
\[ 3x + 2x^2 \]
Add the coefficients and keep one variable
Why: This ignores the different variable parts.
\[ 5x \]
Check with one input
Why: At two, the original gives fourteen, but the wrong simplification gives ten.
\[ 3(2)+2(2)^2=14\quad\text{but}\quad5(2)=10 \]
\[ 3x + 2x^2 \]
Leave unlike terms separate
Why: The variable parts do not match, so there is no combining move.
\[ 2x^2 + 3x \]
Check with the same input
Why: At two, the reordered expression still gives fourteen.
\[ 2(2)^2+3(2)=14\checkmark \]
Notation
Annotate
From Trap: unlike terms do not merge — read this one piece at a time. What is each part doing?
On: \( 3(2)+2(2)^2=14\quad\text{but}\quad5(2)=10 \)
Concept
A factor outside parentheses multiplies every term inside the package.
\[ a(b+c)=ab+ac \]
The most important tutoring move is to point at each inside term before multiplying.
Analogy
Discussion prompt
Explain Distribution opens a package by analogy to something with no Algebra 2 Readiness in it at all — a queue, a recipe, a map, a bank balance, whatever fits. Then say where your analogy breaks.
Hint: An analogy that never breaks is not an analogy, it is the same idea wearing a hat. Find the seam — that is the part that is actually new.
Answer:
A factor outside parentheses multiplies every term inside the package.
Worked example
Distribute and simplify:
\[ 3(2x - 5) + 4x \]
Multiply the outside factor by the first inside term
Why: Three groups of two variable terms make six variable terms.
\[ 6x - 15 + 4x \]
Multiply the outside factor by the second inside term
Why: The negative sign stays attached to the five.
\[ 6x - 15 + 4x \]
Combine like terms
Why: The variable terms match; the constant has no partner.
\[ 10x - 15 \]
Verify with one input
Why: At two, both expressions give five.
\[ 3(2(2)-5)+4(2)=5\quad\text{and}\quad10(2)-15=5\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Model: distribute a positive factor", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: The variable terms match; the constant has no partner.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ 4(x - 6) + 2x \]
Hint: there are two products inside the parentheses
Why: Multiply four by the variable term and by the constant term before combining.
Distribute four to both inside terms
Why: Both pieces inside the package get multiplied.
\[ 4x - 24 + 2x \]
Combine like terms
Why: Only the variable terms combine.
\[ 6x - 24 \]
Check with one input
Why: At five, both expressions give six.
\[ 4(5-6)+2(5)=6\quad\text{and}\quad6(5)-24=6\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Guided try: distribute positive", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Both pieces inside the package get multiplied.
Concept
A minus outside parentheses is a multiplier. It does not merely change the first term.
\[ -1(a-b)=-a+b \]
Say this aloud: negative times positive is negative; negative times negative is positive.
Explain it
Discussion prompt
Explain A negative distributor changes every sign it touches to a student a year behind you. No notation, no jargon they have not met — and it still has to be true.
Hint: If your explanation needs a symbol they have never seen, you are describing the notation rather than the idea.
Answer:
A minus outside parentheses is a multiplier. It does not merely change the first term.
Step zero
Discussion prompt
Model: simplify with a negative distributor — before any calculation: what is the plan? Name the moves in order, in plain English, without doing the arithmetic.
Hint: It starts with: Name the outside multiplier
Answer:
Worked example
Simplify:
\[ 4x - 3(2x - 5) + 7 \]
Name the outside multiplier
Why: The multiplier is negative three, not just three.
\[ -3(2x-5) \]
Multiply the first inside term
Why: Negative three times two variable terms gives negative six variable terms.
\[ 4x - 6x + 15 + 7 \]
Multiply the second inside term
Why: Negative three times negative five gives positive fifteen.
\[ 4x - 6x + 15 + 7 \]
Combine variable terms
Why: Four variable terms minus six variable terms leaves negative two variable terms.
\[ -2x + 15 + 7 \]
Combine constants
Why: Fifteen plus seven is twenty-two.
\[ -2x + 22 \]
Verify by testing one input
Why: At three, both forms give sixteen.
\[ 4(3)-3(2(3)-5)+7=16\quad\text{and}\quad-2(3)+22=16\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Model: simplify with a negative distributor", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Four variable terms minus six variable terms leaves negative two variable terms.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ 2x - (5x - 7) \]
Hint: rewrite the subtraction as negative one times the package
Why: The minus outside the parentheses must touch both inside terms.
Distribute negative one to both inside terms
Why: The first term changes negative, and the negative constant changes positive.
\[ 2x - 5x + 7 \]
Combine the variable terms
Why: Two variable terms minus five variable terms leaves negative three variable terms.
\[ -3x + 7 \]
Check with one input
Why: At four, both expressions give negative five.
\[ 2(4)-(5(4)-7)=-5\quad\text{and}\quad-3(4)+7=-5\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Guided try: parentheses subtraction", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: At four, both expressions give negative five.
Anomaly
Predict first
A student writes this, and it looks reasonable:
Multiply the first term, then keep the second sign unchanged
It is wrong. Say what breaks — and say it before you turn the page.
Correct: This misses the second multiplication by the outside negative.
This misses the second multiplication by the outside negative.
Why: This misses the second multiplication by the outside negative.
Trap
\[ -3(x - 4) \]
Multiply the first term, then keep the second sign unchanged
Why: This misses the second multiplication by the outside negative.
\[ -3x - 12 \]
Check with one value
Why: At one, the original gives nine, but the wrong expression gives negative fifteen.
\[ -3(1-4)=9\quad\text{but}\quad-3(1)-12=-15 \]
\[ -3(x - 4) \]
Multiply both terms by the outside negative
Why: A negative times a negative constant becomes positive.
\[ -3x + 12 \]
Check with the same value
Why: At one, both the original and simplified expressions give nine.
\[ -3(1-4)=9\quad\text{and}\quad-3(1)+12=9\checkmark \]
Notation
Annotate
From Trap: the negative does not stop halfway — read this one piece at a time. What is each part doing?
On: \( -3(1-4)=9\quad\text{and}\quad-3(1)+12=9\checkmark \)
Concept
Solving is a sequence of legal moves that keep both sides equal.
\[ x+7=12 \]
Every move must happen to both sides, and the final answer must work in the original equation.
Explain it
Discussion prompt
Explain Equations stay balanced to a student a year behind you. No notation, no jargon they have not met — and it still has to be true.
Hint: If your explanation needs a symbol they have never seen, you are describing the notation rather than the idea.
Answer:
Solving is a sequence of legal moves that keep both sides equal.
Fill the middle
Fill in the blanks
From Model: one-step equation — finish the line. Write what belongs on the right of the equals sign before you look.
x+7-7 = 12-7
Why: Producing the right-hand side unprompted is the difference between recognising this line and being able to use it. Addition is undone by subtraction, and both sides must change together.
Worked example
Solve:
\[ x+7=12 \]
Identify what is attached to the variable
Why: Seven is being added to the variable.
\[ x+7=12 \]
Use the inverse operation on both sides
Why: Addition is undone by subtraction, and both sides must change together.
\[ x+7-7=12-7 \]
Simplify both sides
Why: The variable is now alone.
\[ x=5 \]
Verify in the original equation
Why: Five plus seven equals twelve.
\[ 5+7=12\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Model: one-step equation", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Addition is undone by subtraction, and both sides must change together.
Estimation
Predict first
Your turn: work this on paper before you reveal the hint.
Commit before you compute: what does Independent try: one-step equation come out to? A rough magnitude and the right form is enough — the point is to have something concrete to be wrong about.
Correct: Add nine to both sides
Why: A prediction you can defend turns the computation into a check rather than a leap of faith — and an answer that contradicts it is caught on the spot. Adding nine undoes subtracting nine while keeping the equation balanced.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ x - 9 = -2 \]
Hint: undo subtraction
Why: Ask what operation would remove a minus nine.
Add nine to both sides
Why: Adding nine undoes subtracting nine while keeping the equation balanced.
\[ x=7 \]
Check in the original equation
Why: Seven minus nine equals negative two.
\[ 7-9=-2\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Independent try: one-step equation", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Adding nine undoes subtracting nine while keeping the equation balanced.
Ranking
Put in order
Put the moves of Model: two-step equation into the order they have to happen.
Why: These are the moves of the worked example in the order it makes them, and each one is set up by the one before it. The minus four was applied after the multiplication by three.
Worked example
Solve:
\[ 3x - 4 = 11 \]
Undo the addition or subtraction first
Why: The minus four was applied after the multiplication by three.
\[ 3x=15 \]
Undo the coefficient second
Why: Divide both sides by three.
\[ x=5 \]
State the answer in test-answer form
Why: The variable is alone, so the answer is ready to check.
\[ x=5 \]
Verify in the original equation
Why: Three times five minus four equals eleven.
\[ 3(5)-4=11\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Model: two-step equation", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Three times five minus four equals eleven.
Hypothesis
Predict first
Guided try: two-step equation is about to be worked. State your hypothesis first: which rule or definition decides this one, and what is the first move it forces? Then watch whether the example agrees with you.
Correct: Hint: clear the constant first
Why: Undo plus six before dividing by the coefficient.
A hypothesis you wrote down is falsifiable; a vague sense of how it will go is not. If the example opens somewhere else, that gap is the thing worth chasing.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ 4x + 6 = -10 \]
Hint: clear the constant first
Why: Undo plus six before dividing by the coefficient.
Subtract six from both sides
Why: This leaves the variable term alone on the left.
\[ 4x=-16 \]
Divide by four
Why: The coefficient is undone last.
\[ x=-4 \]
Check in the original equation
Why: Four times negative four plus six equals negative ten.
\[ 4(-4)+6=-10\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Guided try: two-step equation", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Four times negative four plus six equals negative ten.
Concept
When an equation has parentheses or like terms, do not move terms immediately. First simplify each side on its own.
| Phase | Question |
|---|---|
| clean sides | Can either side be simplified without crossing the equals sign? |
| collect | Where should the variable terms live? |
| undo | What inverse operation isolates the variable? |
| verify | Does the answer satisfy the original? |
Analogy
Discussion prompt
Explain Multi-step equations: clean sides, then undo by analogy to something with no Algebra 2 Readiness in it at all — a queue, a recipe, a map, a bank balance, whatever fits. Then say where your analogy breaks.
Hint: An analogy that never breaks is not an analogy, it is the same idea wearing a hat. Find the seam — that is the part that is actually new.
Answer:
When an equation has parentheses or like terms, do not move terms immediately. First simplify each side on its own.
Worked example
Solve:
\[ 2(3x - 4)=5x+9 \]
Distribute on the left side
Why: Clean the side with parentheses before moving terms.
\[ 6x - 8 = 5x + 9 \]
Subtract the smaller variable term from both sides
Why: This keeps the remaining coefficient positive.
\[ x - 8 = 9 \]
Add eight to both sides
Why: Undo the subtraction around the variable.
\[ x=17 \]
Verify by substituting seventeen into the original equation
Why: Both original sides become ninety-four.
\[ 2(3(17)-4)=94\quad\text{and}\quad5(17)+9=94\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Model: clean sides, then solve", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Undo the subtraction around the variable.
Step zero
Discussion prompt
Guided try: equation with a negative distributor — before any calculation: what is the plan? Name the moves in order, in plain English, without doing the arithmetic.
Hint: It starts with: Hint: distribute before solving
Answer:
Worked example
Your turn: work this on paper before you reveal the hint.
\[ -3(x - 2) + 5 = 14 \]
Hint: distribute before solving
Why: The outside negative multiplies both terms inside the parentheses.
Distribute negative three
Why: Negative three times negative two becomes positive six.
\[ -3x + 6 + 5 = 14 \]
Combine constants on the left
Why: The left side can be cleaned before any balance move.
\[ -3x + 11 = 14 \]
Subtract eleven from both sides
Why: This isolates the variable term.
\[ -3x=3 \]
Divide by negative three
Why: The coefficient is undone last.
\[ x=-1 \]
Check in the original equation
Why: Substituting negative one gives fourteen.
\[ -3((-1)-2)+5=14\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Guided try: equation with a negative distributor", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Substituting negative one gives fourteen.
Anomaly
Predict first
A student writes this, and it looks reasonable:
Subtract five variable terms before distributing
It is wrong. Say what breaks — and say it before you turn the page.
Correct: The terms are not ready to combine because one side still has parentheses.
The terms are not ready to combine because one side still has parentheses.
Why: The terms are not ready to combine because one side still has parentheses.
Trap
\[ 2(3x - 4)=5x+9 \]
Subtract five variable terms before distributing
Why: The terms are not ready to combine because one side still has parentheses.
\[ 2(3x-4)-5x=9 \]
Lose track of what the left side means
Why: The equation becomes harder and sign errors multiply.
\[ 6x-8-5x=9 \]
\[ 2(3x - 4)=5x+9 \]
Distribute first
Why: Cleaning each side makes the next balance move obvious.
\[ 6x-8=5x+9 \]
Then collect variable terms
Why: Now subtracting five variable terms is a clean balance move.
\[ x-8=9\checkmark \]
Two truths and a lie
Sort into buckets
Some of these hold up and some are the exact mistakes this lesson is built to prevent. Sort them.
Concept
Variable terms are quantities too. You can add or subtract them from both sides just like constants.
\[ 5x - 2 = 3x + 8 \]
Choose the move that keeps the remaining coefficient positive when possible.
Counterexample
Discussion prompt
Variable terms are quantities too. You can add or subtract them from both sides just like constants.
That is stated as though it always holds. Do one of two things: produce a case where it fails, or say precisely what rules such a case out. "It just does" is not on the menu.
Hint: Hunt at the extremes first — zero, one, negative, empty, equal. If every extreme survives, the reason they survive is the proof.
Answer:
Choose the move that keeps the remaining coefficient positive when possible.
Fill the middle
Fill in the blanks
From Model: variable on both sides — finish the line. Write what belongs on the right of the equals sign before you look.
5x - 2 = 3x + 8
Why: Producing the right-hand side unprompted is the difference between recognising this line and being able to use it. Collect variables on the side with more variable terms.
Worked example
Solve:
\[ 5x - 2 = 3x + 8 \]
Subtract three variable terms from both sides
Why: Collect variables on the side with more variable terms.
\[ 2x - 2 = 8 \]
Add two to both sides
Why: Clear the constant from the variable side.
\[ 2x=10 \]
Divide by two
Why: Undo the coefficient.
\[ x=5 \]
Verify in both original sides
Why: Both sides become twenty-three.
\[ 5(5)-2=23\quad\text{and}\quad3(5)+8=23\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Model: variable on both sides", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Clear the constant from the variable side.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ 7x + 4 = 2x - 11 \]
Hint: keep the variable coefficient positive
Why: Move the smaller variable term to the other side.
Subtract two variable terms from both sides
Why: This leaves five variable terms on the left.
\[ 5x+4=-11 \]
Subtract four from both sides
Why: Clear the constant from the variable side.
\[ 5x=-15 \]
Divide by five
Why: The coefficient is undone last.
\[ x=-3 \]
Check in the original equation
Why: Both sides become negative seventeen.
\[ 7(-3)+4=-17\quad\text{and}\quad2(-3)-11=-17\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Independent try: variable on both sides", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: Clear the constant from the variable side.
Concept
A literal equation has several letters, but only one target variable. Treat every other letter as a known quantity.
\[ A=\frac{1}{2}bh \]
target variable — The variable that must be alone at the end.
Matching
Match the pairs
Match each term to the definition this lesson gave it — not the one you would guess from the word.
Why: These are the working definitions of term, coefficient, target variable as Week 1: Expressions, Equations, and Literal Equations uses them. Pairing them correctly is the test of whether you could state each one with the slide switched off.
Fill the middle
Fill in the blanks
From Model: solve a formula for height — finish the line. Write what belongs on the right of the equals sign before you look.
\fracA\checkmark___b\left(\frac______\right) = ___
Why: Producing the right-hand side unprompted is the difference between recognising this line and being able to use it. The target is multiplied by b and by one half.
Worked example
Solve for the target variable:
\[ A=\frac{1}{2}bh\qquad\text{target: }h \]
Identify what is attached to the target
Why: The target is multiplied by b and by one half.
\[ A=\frac{1}{2}bh \]
Multiply both sides by two
Why: This removes the factor of one half.
\[ 2A=bh \]
Divide both sides by b
Why: This leaves the target variable alone.
\[ h=\frac{2A}{b} \]
Verify by substituting the rearranged expression
Why: The original formula simplifies back to A.
\[ \frac{1}{2}b\left(\frac{2A}{b}\right)=A\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Model: solve a formula for height", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: The original formula simplifies back to A.
Estimation
Predict first
Your turn: work this on paper before you reveal the hint.
Commit before you compute: what does Guided try: solve slope-intercept form for the input come out to? A rough magnitude and the right form is enough — the point is to have something concrete to be wrong about.
Correct: Divide both sides by m
Why: A prediction you can defend turns the computation into a check rather than a leap of faith — and an answer that contradicts it is caught on the spot. This removes the coefficient attached to the target.
Worked example
Your turn: work this on paper before you reveal the hint.
\[ y=mx+b\qquad\text{target: }x \]
Hint: remove the added constant before dividing
Why: Treat m and b like known numbers while isolating the target.
Subtract b from both sides
Why: This clears the added constant.
\[ y-b=mx \]
Divide both sides by m
Why: This removes the coefficient attached to the target.
\[ x=\frac{y-b}{m} \]
Check by substituting the expression back
Why: The right side simplifies to y.
\[ m\left(\frac{y-b}{m}\right)+b=y-b+b=y\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Guided try: solve slope-intercept form for the input", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: This removes the coefficient attached to the target.
Step zero
Discussion prompt
Independent try: solve a perimeter formula — before any calculation: what is the plan? Name the moves in order, in plain English, without doing the arithmetic.
Hint: It starts with: Hint: clear the term that does not contain the target
Answer:
Worked example
Your turn: work this on paper before you reveal the hint.
\[ P=2l+2w\qquad\text{target: }w \]
Hint: clear the term that does not contain the target
Why: The target term is two times width.
Subtract two lengths from both sides
Why: This leaves the target term on the right.
\[ P-2l=2w \]
Divide both sides by two
Why: This leaves the target variable alone.
\[ w=\frac{P-2l}{2} \]
Check by substituting the expression back
Why: The formula simplifies back to P.
\[ 2l+2\left(\frac{P-2l}{2}\right)=2l+P-2l=P\checkmark \]
Picture it
Animation
Shows: Each line of the worked example "Independent try: solve a perimeter formula", appearing one at a time.
The same working the example does, in the order a tutor would write it.
Takeaway: This leaves the target term on the right.
Concept
Use this map after the tutoring hour. The daily homework should feel familiar because the deck already rehearsed the moves.
| Day | Focus | Assignment |
|---|---|---|
| 1 | combine like terms | 25 problems, at least 10 with negatives |
| 2 | distribute | 25 problems, including parentheses subtraction |
| 3 | mixed simplifying | 20 problems plus 5 find-the-error problems |
| 4 | multi-step equations | 20 problems with inverse operations shown |
| 5 | literal equations | 15 formula rearrangements |
| 6 | mixed quiz | 25 questions from Week 1 |
| 7 | corrections | redo misses, then 10 fresh mixed problems |
Trade off
Comparison matrix
From Daily practice map: every row here is a choice with a cost. Fill the Assignment column, then say which row you would actually pick and what you give up for it.
| Day | Focus | Assignment |
|---|---|---|
| 1 | combine like terms | 25 problems, at least 10 with negatives |
| 2 | distribute | 25 problems, including parentheses subtraction |
| 3 | mixed simplifying | 20 problems plus 5 find-the-error problems |
| 4 | multi-step equations | 20 problems with inverse operations shown |
| 5 | literal equations | 15 formula rearrangements |
| 6 | mixed quiz | 25 questions from Week 1 |
| 7 | corrections | redo misses, then 10 fresh mixed problems |
Pattern
1. Sort terms before calculating
Why: This prevents unlike terms from being combined.
2. Distribute to every term inside parentheses
Why: A factor outside the package touches every inside term.
3. Clean each side before solving
Why: Distribution and like-term combining happen before balance moves.
4. Undo operations on both sides
Why: Equations stay true only when both sides change together.
5. Verify in the original problem
Why: Original-problem verification catches sign errors and skipped steps.
Real world
Discussion prompt
Outside this lesson: where does Week 1: Expressions, Equations, and Literal Equations actually turn up? Name one concrete situation — a job, a piece of software someone ships, a decision somebody has to make — and say which part of Week 1 master procedure is doing the work in it.
Hint: Vague is the failure mode here. "Engineering" is not a situation; "deciding whether this build is fast enough to ship" is.
Answer:
An hour-length bridge deck of 40 slides that fills a full tutoring hour. It covers terms and like terms, distribution, working with negative signs, multi-step equations, and literal equations, then moves through guided practice and independent practice, with traps and checks along the way.
Check
Work it fully on paper first. Then choose the simplified form.
Check your understanding
Simplify: 4x - 3(2x - 5) + 7
Answer: A
Why: Distribute the negative three to both inside terms: 4x - 6x + 15 + 7. Then combine like terms to get -2x + 22.
Check
Clean the side with parentheses before moving terms.
Check your understanding
Solve: 2(3x - 4) = 5x + 9
Answer: A
Why: Distribute first: 6x - 8 = 5x + 9. Subtract 5x from both sides to get x - 8 = 9, then add 8. The solution is x = 17.
Check
Treat every non-target letter like a known quantity.
Check your understanding
Solve A = (1/2)bh for h.
Answer: A
Why: Multiply both sides by 2 to get 2A = bh. Then divide both sides by b to get h = 2A / b.
Ranking
Put in order
Put the moves of Independent mini exit ticket into the order they have to happen.
Why: These are the moves of the worked example in the order it makes them, and each one is set up by the one before it. Sort, distribute, clean, undo, and verify.
Worked example
Try all three without revealing the answers. Write one correction sentence for any miss.
| Problem | Task |
|---|---|
| 1 | Simplify the expression. |
| 2 | Solve the equation. |
| 3 | Solve the formula for the target. |
\[ 3x-(2x-9)+5\qquad4(x-2)=2x+10\qquad C=\frac{5}{9}(F-32)\text{ for }F \]
Hint: use the Week 1 procedure
Why: Sort, distribute, clean, undo, and verify.
Solve the three problems
Why: Compare your work to the answer forms only after you have attempted all three.
| Problem | Answer |
|---|---|
| 1 | x + 14 |
| 2 | x = 9 |
| 3 | F = 9C / 5 + 32 |
Check each answer
Why: Substitute a simple value or the solved expression back into the original to confirm the result.
| Problem | Check |
|---|---|
| 1 | try x = 1; both forms give 15 |
| 2 | 4(9 - 2) = 28 and 2(9) + 10 = 28 |
| 3 | substitution simplifies back to C |
Comparison
Comparison matrix
From Independent mini exit ticket: refill the Task column from what you know. The rest of the table is as it appeared.
| Problem | Task |
|---|---|
| 1 | Simplify the expression. |
| 2 | Solve the equation. |
| 3 | Solve the formula for the target. |
Connect it up
Draw it
One page, no notation unless you need it: draw how these connect — Week 1 master procedure · How this hour will run · Correction rule for every miss · First, sort the pieces · Like terms must match exactly. Put an arrow wherever one of them is what makes another possible, and label the arrow with why.
Recap
This hour gives the student a repeatable algebra routine: sort terms, distribute carefully, combine only true like terms, solve by legal balance moves, and verify in the original.
| Skill | Student can say |
|---|---|
| terms | I know what pieces can combine. |
| distribution | The outside factor touches every inside term. |
| equations | I clean sides first, then undo. |
| literal equations | I isolate the target variable. |
| corrections | I can name the exact mistake. |
Want this taught 1-on-1? Alexander tutors Algebra 2 Readiness — $55/session, free consultation.