Find the inverse of a 2×2 matrix using the adjugate formula, and verify A·A⁻¹ = I.
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A⁻¹ = (1/det(A)) · adj(A)
For a 2×2 matrix A = [[a,b],[c,d]]:
1. Compute det(A) = ad − bc.
2. Form the adjugate: swap the diagonal entries (a ↔ d) and negate the off-diagonal entries (b → −b, c → −c).
3. Divide every entry by det(A).
Result: A⁻¹ = (1/det) · [[d, −b], [−c, a]]
Only works when det(A) ≠ 0. A matrix with zero determinant is called singular and has no inverse.
Ax = b → x = A⁻¹b
Solving matrix equations: A⁻¹ lets you "undo" matrix multiplication. If Ax = b, multiply both sides on the left by A⁻¹ to get x = A⁻¹b — just like dividing both sides of a scalar equation.
Invertible = nonsingular = full rank: An invertible 2×2 matrix has det ≠ 0, rank 2, and its two rows (or columns) are linearly independent.
A singular matrix maps the plane to a line or a point — information is lost. There is no way to "undo" that collapse, so no inverse exists.
One-on-one Algebra 2 tutoring builds real intuition for why inverses exist, when they don't, and how to use them to solve systems — we work through your homework and tests until it clicks.